题目链接
#include
#include
#include
#include
using namespace std;
int A, B, C, D;
double f[20][20][20][20][5][5];
bool vis[20][20][20][20][5][5];
double dp(int a, int b, int c, int d, int x, int y){
if(vis[a][b][c][d][x][y] == true) return f[a][b][c][d][x][y];
vis[a][b][c][d][x][y] = true;
double &res = f[a][b][c][d][x][y]; res = 0.0;
int ta = a, tb = b, tc = c, td = d;
if(x == 1) ta++; if(x == 2) tb++; if(x == 3) tc++; if(x == 4) td++;
if(y == 1) ta++; if(y == 2) tb++; if(y == 3) tc++; if(y == 4) td++;
if(ta >= A && tb >= B && tc >= C && td >= D) return res = 0.0;
int rest = 54 - ta - tb - tc - td; //剩下的牌数
if(rest <= 0) return res = 1e10;
if(a < 13) res += dp(a+1, b, c, d, x, y) * (13 - a) / rest;
if(b < 13) res += dp(a, b+1, c, d, x, y) * (13 - b) / rest;
if(c < 13) res += dp(a, b, c+1, d, x, y) * (13 - c) / rest;
if(d < 13) res += dp(a, b, c, d+1, x, y) * (13 - d) / rest;
if(x == 0){ //考虑下一步抽到小王
double tmp = dp(a, b, c, d, 1, y);
tmp = min(tmp, dp(a, b, c, d, 2, y));
tmp = min(tmp, dp(a, b, c, d, 3, y));
tmp = min(tmp, dp(a, b, c, d, 4, y));
res += tmp / rest;
}
if(y == 0){
double tmp = dp(a, b, c, d, x, 1);
tmp = min(tmp, dp(a, b, c, d, x, 2));
tmp = min(tmp, dp(a, b, c, d, x, 3));
tmp = min(tmp, dp(a, b, c, d, x, 4));
res += tmp / rest;
}
return ++res;
}
int main()
{
scanf("%d %d %d %d", &A, &B, &C, &D);
double ans = dp(0, 0, 0, 0, 0, 0);
if(ans > 100) printf("-1.000\n");
else printf("%.3f\n", ans);
return 0;
}