两种抽奖功能实现(走马灯)

今天做了两种抽奖的走马灯功能, 一般来说, 抽奖的奖品是通过后台返回回来的, 不过因为是自己做的一个小demo, 因此就直接封装成了对象, 自己往对象里面传值实现抽奖

 先来看一下第一种, 先上HTML和CSS

<div id="b_circle">
   <div  id="b_circle_c">
     <img src="./1.png" alt="">
   div>
   <div id="s_circle"><div class="arrow">div>div>
div>

    #b_circle {
      width: 500px;
      height: 500px;
      margin: 100px auto;
      border: 1px solid #ccc;
      border-radius: 50%;
      position: relative;
    }
    #b_circle_c {
      width: 500px;
      height: 500px;
      border: 1px solid #ccc;
      border-radius: 50%;
      transform: rotate(0deg);
    }
    #s_circle {
      width: 200px;
      height: 200px;
      position: absolute;
      top: 50%;
      left: 50%;
      transform: translate(-50%,-50%);
      background-color: red;
      border-radius: 50%;
    }
    .arrow {
      width: 3px;
      height: 80%;
      position: absolute;
      left: 50%;
      transform: translateX(-50%);
      top: -40px;
      background-color: blue;
    }
    img {
      width: 100%;
    }

我做的转盘抽奖的答题思路就是, 利用transform中的rotate属性, 以及transition的过度效果, 为转盘添加旋转动画, 下面是JS代码:

  function Rotate (ele,num) {
    this.box = document.getElementById(ele)
    this.start = document.getElementById('s_circle')
    this.timer = null   //定时器
    this.endDe = 0    //第一次定时器旋转结束时的角度
    this.count = 0    //利用开闭原则, 防止多次点击抽奖
    this.start.onclick = () => {
      if(this.count === 0) {
        this.count=1
        this.roll(num)
      }
    } 
  }

  Rotate.prototype.roll = function(num) {
   //让装盘旋转三圈加上奖品对应的度数
    this.box.style.transform="rotate("+(1440+ num*45-20)+"deg)"
    this.box.style.transition="all 9s cubic-bezier(0,0,0.25,1)"this.timer = setTimeout(()=>{    //转完之后, 让转盘的旋转角度变为奖品对应的度数, 并赋值给endDe变量
      this.count=0
      this.box.style.transition=""
      this.endDe =  this.box.style.transform.slice(7,this.box.style.transform.indexOf('d'))%360
      this.box.style.transform="rotate("+this.endDe+"deg)"
      switch(true){
        case this.endDe<=45:
          alert("一等奖")
          break
        case this.endDe<=90:
          alert("二等奖")
          break
        case this.endDe<=135:
          alert("三等奖")
          break
        case this.endDe<=180:
          alert("四等奖")
          break
        case this.endDe<=225:
          alert("五等奖")
          break
        case this.endDe<=270:
          alert("六等奖")
          break
        case this.endDe<=315:
          alert("七等奖")
          break
        case this.endDe<=360:
          alert("八等奖")
          break   
      }
    },90000)
  }

  var rotate = new Rotate('b_circle_c',6)

效果如图:

 

第二种抽奖: 

<div id="box">
    <ul id='ul'>
      <li class="li">1li>
      <li class="li">2li>
      <li class="li">3li>
      <li class="li">4li>
      <li class="li1" id="chou">点击li>
      <li class="li">6li>
      <li class="li">Iphone全家桶li>
      <li class="li">8li>
      <li class="li">9li>
    ul>
div>

#box {
    width: 400px;
    height: 400px;
    margin: 100px auto;
    position: relative;
    background-color: pink;
  }    
  #ul {
    width: 100%;
    height: 100%;
    position: absolute;
    padding: 20px;
    box-sizing: border-box;
    display: flex;
    flex-wrap: wrap;
    justify-content: space-between;
  }
  .li,.li1 {
    width: 30%;
    height: 30%;
    background-color: skyblue;
    list-style: none;
  }
  .chose {
    background-color: #fff;
  }

第二种抽奖的思路就是通过添加和删除类名, 来实现移动的效果, 同样也是用定时器, 当点击抽奖的时候, 触发定时器, 让一个元素高亮, 再通过回调自身, 来循环实现这种效果, JS代码如下: 

function Chose (ele,num) {
    this.box = document.getElementById(ele),
    this.li = document.getElementsByClassName('li')
    this.cli = document.getElementById('chou')
    this.timer = null
    this.speed = 50   //定时器触发的速度
    this.count = 0;   //计数变量
    this.cli.onclick = ()=>{
      let date = new Date().getTime()
      this.move(num,date)
    }
  }

    Chose.prototype.move = function(num,date) {
    this.timer = setTimeout(()=>{
        let date2 = new Date().getTime()
        let j = this.count    //因为元素的顺序,并不是环形的, 所以这里设置一个变量j, 来设置正确的高亮元素
        for(let i=0; i<this.li.length;i++) {
          this.li[i].classList.remove("chose");
        }
        switch(this.count) {
          case 3:
            j = 4
            break
          case 4:
            j = 7
            break
          case 5:
            j = 6
            break
          case 6:
            j = 5
            break  
          case 7:
            j = 3
            break 
        }
        this.li[j].classList.add("chose");
        this.count++
        if(this.count > 7 ) {
          this.count = 0
        }
        if(date2-date>2000){    //如果时间大于2秒, 则让速度慢下来
          this.speed +=30 
          if(num-1 === j && date2-date>5000){   //如果时间大于5秒, 并且转到了奖品项上, 则停止计时器
            setTimeout(()=>{
              alert(this.li[j].innerText)
　　　　　　　　 this.speed = 50
            },0)
            return
          }
        }
        this.move(num,date)
      },this.speed)
      
  }
  var chose = new Chose('box', 6)

效果图如下: 

 

转载于:https://www.cnblogs.com/luckq/p/9469268.html