抖音分享页面signature
追了一天代码，发现没啥用。他这个生成signature的算法本身有问题。
以目前的情况看，不给sign值直接请求也是有一定几率成功获取数据的。
所以说现在还是等页面更新吧，暂时把这个放一放。
接口链接==>>(多刷新几次就有了)
下面的没什么用、我先记到这里
nonce 是 uid, 可以为None.
sec_uid 是用户对应的ID: “MS4wLjABAAAAshzXgVS8HqF8PomFlCATZjkjC48Az0d8tk28RXRgrbA”
查询 _bytedAcrawler 。
可以发现 webpack_require 函数定义了一个可以在浏览器中执行的加载函数，来模拟Node.js中的require语句。
(function anonymous() {
function e(e, a, r) {
return (b[e] || (b[e] = t("x,y", "return x " + e + " y")))(r, a)
}
function a(e, a, r) {
return (k[r] || (k[r] = t("x,y", "return new x[y](" + Array(r + 1).join(",x[++y]").substr(1) + ")")))(e, a)
}
function r(e, a, r) {
var n, t, s = {}, b = s.d = r ? r.d + 1 : 0;
for (s["$" + b] = s,
t = 0; t < b; t++)
s[n = "$" + t] = r[n];
for (t = 0,
b = s.length = a.length; t < b; t++)
s[t] = a[t];
return c(e, 0, s)
}
function c(t, b, k) {
function u(e) {
v[x++] = e
}
function f() {
return g = t.charCodeAt(b++) - 32,
t.substring(b, b += g)
}
function l() {
try {
y = c(t, b, k)
} catch (e) {
h = e,
y = l
}
}
for (var h, y, d, g, v = [], x = 0; ; )
switch (g = t.charCodeAt(b++) - 32) {
case 1:
u(!v[--x]);
break;
case 4:
v[x++] = f();
break;
case 5:
u(function(e) {
var a = 0
, r = e.length;
return function() {
var c = a < r;
return c && u(e[a++]),
c
}
}(v[--x]));
break;
case 6:
y = v[--x],
u(v[--x](y));
break;
case 8:
if (g = t.charCodeAt(b++) - 32,
l(),
b += g,
g = t.charCodeAt(b++) - 32,
y === c)
b += g;
else if (y !== l)
return y;
break;
case 9:
v[x++] = c;
break;
case 10:
u(s(v[--x]));
break;
case 11:
y = v[--x],
u(v[--x] + y);
break;
case 12:
for (y = f(),
d = [],
g = 0; g < y.length; g++)
d[g] = y.charCodeAt(g) ^ g + y.length;
u(String.fromCharCode.apply(null, d));
break;
case 13:
y = v[--x],
h = delete v[--x][y];
break;
case 14:
v[x++] = t.charCodeAt(b++) - 32;
break;
case 59:
u((g = t.charCodeAt(b++) - 32) ? (y = x,
v.slice(x -= g, y)) : []);
break;
case 61:
u(v[--x][t.charCodeAt(b++) - 32]);
break;
case 62:
g = v[--x],
k[0] = 65599 * k[0] + k[1].charCodeAt(g) >>> 0;
break;
case 65:
h = v[--x],
y = v[--x],
v[--x][y] = h;
break;
case 66:
u(e(t[b++], v[--x], v[--x]));
break;
case 67:
y = v[--x],
d = v[--x],
u((g = v[--x]).x === c ? r(g.y, y, k) : g.apply(d, y));
break;
case 68:
u(e((g = t[b++]) < "<" ? (b--,
f()) : g + g, v[--x], v[--x]));
break;
case 70:
u(!1);
break;
case 71:
v[x++] = n;
break;
case 72:
v[x++] = +f();
break;
case 73:
u(parseInt(f(), 36));
break;
case 75:
if (v[--x]) {
b++;
break
}
case 74:
g = t.charCodeAt(b++) - 32 << 16 >> 16,
b += g;
break;
case 76:
u(k[t.charCodeAt(b++) - 32]);
break;
case 77:
y = v[--x],
u(v[--x][y]);
break;
case 78:
g = t.charCodeAt(b++) - 32,
u(a(v, x -= g + 1, g));
break;
case 79:
g = t.charCodeAt(b++) - 32,
u(k["$" + g]);
break;
case 81:
h = v[--x],
v[--x][f()] = h;
break;
case 82:
u(v[--x][f()]);
break;
case 83:
h = v[--x],
k[t.charCodeAt(b++) - 32] = h;
break;
case 84:
v[x++] = !0;
break;
case 85:
v[x++] = void 0;
break;
case 86:
u(v[x - 1]);
break;
case 88:
h = v[--x],
y = v[--x],
v[x++] = h,
v[x++] = y;
break;
case 89:
u(function() {
function e() {
return r(e.y, arguments, k)
}
return e.y = f(),
e.x = c,
e
}());
break;
case 90:
v[x++] = null;
break;
case 91:
v[x++] = h;
break;
case 93:
h = v[--x];
break;
case 0:
return v[--x];
default:
u((g << 16 >> 16) - 16)
}
}
var n = this
, t = n.Function
, s = Object.keys || function(e) {
var a = {}
, r = 0;
for (var c in e)
a[r++] = c;
return a.length = r,
a
}
, b = {}
, k = {};
return r
}());