Oracle 高级查询之二 分析函数部分--first_value,last_value
ORACLE函数：LAST_VALUE,FIRST_VALUE的用法：
1、初始化原始数据：
create table test (id number(2), name varchar2(10), salary number(6,2));
insert into test values (1,'Tom',120);
insert into test values (2,'Ellen',240);
insert into test values (2,'Joe',80);
insert into test values (3,'Andy',300);
insert into test values (3,'Kary',500);
insert into test values (3,'Erick',1300);
insert into test values (3,'Hou',40);
insert into test values (3,'Mary',200);
insert into test values (3,'Secooler',800);
commit;
select * from test order by ID,name;
ID NAME SALARY
--- ---------- --------
1 Tom 120.00
2 Ellen 240.00
2 Joe 80.00
3 Andy 300.00
3 Erick 1300.00
3 Hou 40.00
3 Kary 500.00
3 Mary 200.00
3 Secooler 800.00
2、LAST_VALUE分析函数的简单用法
（1）在TEST表中添加一列，标识每一个数据分区中薪水最高的人名。
select ID, name, salary, LAST_VALUE(name) OVER (partition by ID order by salary ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) as highest_sal_name from test order by ID, name;
ID NAME SALARY HIGHEST_SAL_NAME
--- ---------- -------- ----------------
1 Tom 120.00 Tom
2 Ellen 240.00 Ellen
2 Joe 80.00 Ellen
3 Andy 300.00 Erick
3 Erick 1300.00 Erick
3 Hou 40.00 Erick
3 Kary 500.00 Erick
3 Mary 200.00 Erick
3 Secooler 800.00 Erick
注意其中“ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING”的使用，若省略效果如下。
select ID, name, salary, LAST_VALUE(name) OVER (partition by ID order by salary) as highest_sal_name from test order by ID,name;
ID NAME SALARY HIGHEST_SAL_NAME
--- ---------- -------- ----------------
1 Tom 120.00 Tom
2 Ellen 240.00 Ellen
2 Joe 80.00 Joe
3 Andy 300.00 Andy
3 Erick 1300.00 Erick
3 Hou 40.00 Hou
3 Kary 500.00 Kary
3 Mary 200.00 Mary
3 Secooler 800.00 Secooler
显然这不是我们想要的效果:(，这是为什么呢~~~？给您一次思考和回答的机会。
如果对UNBOUNDED PRECEDING和UNBOUNDED FOLLOWING不熟悉，请参考Oracle官方文档“windowing_clause”http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions001.htm#i97640。
在TEST表中添加一列，标识每一个数据分区中薪水最高的薪水值。
col highest_sal_name for 9999
select ID, name, salary, LAST_VALUE(SALARY) OVER (partition by ID order by salary ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) as highest_sal_name from test order by ID, name;
ID NAME SALARY HIGHEST_SAL_NAME
--- ---------- -------- ----------------
1 Tom 120.00 120
2 Ellen 240.00 240
2 Joe 80.00 240
3 Andy 300.00 1300
3 Erick 1300.00 1300
3 Hou 40.00 1300
3 Kary 500.00 1300
3 Mary 200.00 1300
3 Secooler 800.00 1300
3、与之相对应的是FIRST_VALUE函数
select ID, name, salary, FIRST_VALUE(name) OVER (partition by ID order by salary ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) as highest_sal_name from test order by ID, name;
ID NAME SALARY HIGHEST_SAL_NAME
--- ---------- -------- ----------------
1 Tom 120.00 Tom
2 Ellen 240.00 Joe
2 Joe 80.00 Joe
3 Andy 300.00 Hou
3 Erick 1300.00 Hou
3 Hou 40.00 Hou
3 Kary 500.00 Hou
3 Mary 200.00 Hou
3 Secooler 800.00 Hou
select ID, name, salary, FIRST_VALUE(SALARY) OVER (partition by ID order by salary ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) as highest_sal_name from test order by ID, name;
ID NAME SALARY HIGHEST_SAL_NAME
--- ---------- -------- ----------------
1 Tom 120.00 120
2 Ellen 240.00 80
2 Joe 80.00 80
3 Andy 300.00 40
3 Erick 1300.00 40
3 Hou 40.00 40
3 Kary 500.00 40
3 Mary 200.00 40
3 Secooler 800.00 40
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