python中round()函数精度问题

python数据精度问题：

import numpy as np
print(np.around(0.155, 2))
print(np.around(0.005, 2))

手写实现四舍五入：

def round_up(number,power=0):
    """
    实现精确四舍五入，包含正、负小数多种场景
    :param number: 需要四舍五入的小数
    :param power: 四舍五入位数，支持0-∞
    :return: 返回四舍五入后的结果
    """
    digit = 10 ** power
    num2 = float(int(number * digit))
    # 处理正数，power不为0的情况
    if number>=0 and power !=0:
        tag = number * digit - num2 + 1 / (digit * 10)
        if tag>=0.5:
            return (num2+1)/digit
        else:
            return num2/digit
    # 处理正数，power为0取整的情况
    elif  number>=0 and power==0 :
        tag = number * digit - int(number)
        if tag >= 0.5:
            return (num2 + 1) / digit
        else:
            return num2 / digit
    # 处理负数，power为0取整的情况
    elif power==0 and number<0:
        tag = number * digit - int(number)
        if tag <= -0.5:
            return (num2 - 1) / digit
        else:
            return num2 / digit
    # 处理负数，power不为0的情况
    else:
        tag = number * digit - num2 - 1 / (digit * 10)
        if tag <= -0.5:
            return (num2-1)/digit
        else:
            return num2/digit