IE8兼容js原生函数问题(举例map,filter,indexof)

兼容问题后续---------

一些JS的原生函数也不被IE8支持的解决办法(其实就是重写方法):

类似于数组的indeOf()方法:


 if (!Array.prototype.indexOf) {
        Array.prototype.indexOf = function (elt) {

            //获取数组长度向下取整的数值,这里用位移运算符是为了确保返回的是非负整数
            var len = this.length >>> 0;

           //获取这个函数的第二个参数的数值,也就是从第几个下标值开始索引,如果没有,那么默认为0
            var from = Number(arguments[1]) || 0;

            //对第二个参数进行处理,如果大于等于0,向下取整;如果小于等于0,向上取整
            from = (from < 0)
                 ? Math.ceil(from)
                 : Math.floor(from);

            //将负数转换成反向含义
            if (from < 0)
                from += len;
            for (; from < len; from++) {

                //格式:(变量 in 对象)......注意
                //当“对象”为数组时,“变量”指的是数组的“索引”;
                //当“对象”为对象是,“变量”指的是对象的“属性”
                //当from满足数组的索引并且传入的elt等于该数组对应索引下的数值时,返回该索引
                if (from in this &&
                    this[from] === elt)
                    return from;
            }

            //找不到,返回-1
            return -1;
        };
    }

方然,其他的方法类似:

Array的map()方法:

if (!Array.prototype.map) {
        Array.prototype.map = function (callback, thisArg) {

            var T, A, k;

            if (this == null) {
                throw new TypeError(" this is null or not defined");
            }

            var O = Object(this);

            var len = O.length >>> 0;

            if (typeof callback !== "function") {
                throw new TypeError(callback + " is not a function");
            }
            if (thisArg) {
                T = thisArg;
            }
            A = new Array(len);
            k = 0;
            while (k < len) {

                var kValue, mappedValue;

                if (k in O) {

                    kValue = O[k];

                    mappedValue = callback.call(T, kValue, k, O);

                    A[k] = mappedValue;
                }
                k++;
            }

            return A;
        };
    }

Array的filter()方法:

 if (!Array.prototype.filter) {
        Array.prototype.filter = function (fun ) {
            var len = this.length;
            if (typeof fun != "function") {
                throw new TypeError();
            }
            var res = new Array();
            var thisp = arguments[1];
            for (var i = 0; i < len; i++) {
                if (i in this) {
                    var val = this[i];
                    if (fun.call(thisp, val, i, this)) {
                        res.push(val);
                    }
                }
            }
            return res;
        };
    }

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