JPA查询关键字

JPA查询关键字

Spring Data JPA使用方法名可解决大部分的查询问题，但是也存在不能解决所有问题，以下是方法名中支持的关键字：

关键字	简单示例	JPQL片段示例
AND	findByLastNameAndFirstName	WHERE Entity.lastName = ?1 AND Entity.firstName = ?2
IsNull	findByAddressIsNull	WHERE Entity.address is NULL
IsNotNull	readByAddressIsNotNull	WHERE Entity.address NOT NULL
NotNull	readByAddressNotNull	WHERE Entity.address NOT NULL
OR	readByLastNameOrFirstName	WHERE Entity.lastName = ?1 OR Entity.firstName = ?2
Between	getByStartDateBetween	WHERE Entity.startDate BETWEEN ?1 AND ?2
LessThan	findByAgeLessThan	WHERE Entity.age < ?1
GreaterThan	readByAgeGreaterThan	WHERE Entity.age > ?1
After只作用在时间	findByStartDateAfter	WHERE Entity.startDate > ?1
Before只作用在时间	findByStartDateBefore	WHERE Entity.startDate < ?1
LessThanEqual	findByAgeLessThenEqual	WHERE Entity.age <= ?1
GreaterThanEqual	readByAgeGreaterThenEqual	WHERE Entity.age >= ?1
Is	findByLastNameIs	WHERE Entity.lastName = ?1
Equal	getByFirstNameEqual	WHERE Entity.firstName = ?1
Like	findByNameLike	WHERE Entity.name LIKE ? 不包括'%'符号
Not Like	findByNameNotLike	WHERE Entity.name not like ?1 不包括'%'符号
StartingWith	readByNameStartingWith	WHERE Entity.name like ‘?1%’条件以'%'符号结尾
EndingWith	readByName EndingWith	WHERE Entity.name like ‘%?1’条件以'%'符号开头
Containing	getByNameContaining	WHERE Entity.name like ‘%?1%’ 包含'%'符号
OrderBy	findByAgeOrderByAddressDesc	WHERE Entity.age = ? Order By Entity.address DESC
Not	readByAgeNot	WHERE Entity.age <> ?1 不等于
In	findByNameIn(Collection name)	WHERE Entity.name IN (?1 ,?2, ?3)
NotIn	getByNameNotIn(Collection name)	WHERE Entity.name NOT IN (?1 ,?2, ?3)
True	readByFloagTrue()	WHERE Entity.floag = true
False	readByFloagFalse()	WHERE Entity.floag = false
IgnoreCase	findByNameIgnoreCase	WHERE UPPER(Entity.Name) = UPPER(?1)