牛客网暑期ACM多校训练营（第一场）D.Two Graphs（图的同构）

链接：https://www.nowcoder.com/acm/contest/139/D
来源：牛客网
 

题目描述

Two undirected simple graphs and where are isomorphic when there exists a bijection on V satisfying  if and only if {x, y} ∈ E2.
Given two graphs and , count the number of graphs satisfying the following condition:
* .
* G1 and G are isomorphic.

输入描述:

The input consists of several test cases and is terminated by end-of-file.
The first line of each test case contains three integers n, m1 and m2 where |E1| = m1 and |E2| = m2.
The i-th of the following m1 lines contains 2 integers ai and bi which denote {ai, bi} ∈ E1.
The i-th of the last m2 lines contains 2 integers ai and bi which denote {ai, bi} ∈ E2.

输出描述:

For each test case, print an integer which denotes the result.

示例1

输入

复制

3 1 2
1 3
1 2
2 3
4 2 3
1 2
1 3
4 1
4 2
4 3

输出

复制

2
3

备注:

* 1 ≤ n ≤ 8
* 
* 1 ≤ ai, bi ≤ n
* The number of test cases does not exceed 50.

题意：

　　n个点，m1条边的图E1，n个点，m2条边的图E2。求图E2有多少子图跟图E1同构。

题解：

　　用STL的全排列函数next_permutation()枚举映射。对于每一种映射枚举每一条边判断合法性。

　　总情况数要除以图E1的自同构数去重。

//Sinhaeng Hhjian
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