Lua 5.1 位操作（与，或，异或操作）

由于lua5.1不支持位操作，自己写了一个lua的位操作函数，代码如下：

方法1：

function Xor(num1,num2)
	local tmp1 = num1
	local tmp2 = num2
	local str = ""
	repeat
		local s1 = tmp1 % 2
		local s2 = tmp2 % 2
		if s1 == s2 then
			str = "0"..str
		else
			str = "1"..str
		end
		tmp1 = math.modf(tmp1/2)
		tmp2 = math.modf(tmp2/2)
	until(tmp1 == 0 and tmp2 == 0)
	return tonumber(str,2)
end

function And(num1,num2)
	local tmp1 = num1
	local tmp2 = num2
	local str = ""
	repeat
		local s1 = tmp1 % 2
		local s2 = tmp2 % 2
		if s1 == s2 then
			if s1 == 1 then
				str = "1"..str
			else
				str = "0"..str
			end
		else
			str = "0"..str
		end
		tmp1 = math.modf(tmp1/2)
		tmp2 = math.modf(tmp2/2)
	until(tmp1 == 0 and tmp2 == 0)
	return tonumber(str,2)
end

function Or(num1,num2)
	local tmp1 = num1
	local tmp2 = num2
	local str = ""
	repeat 
		local s1 = tmp1 % 2
		local s2 = tmp2 % 2
		if s1 == s2 then
			if s1 == 0 then
				str = "0"..str
			else
				str = "1"..str
			end
		else
			str = "1"..str
		end
		tmp1 = math.modf(tmp1/2)
		tmp2 = math.modf(tmp2/2)
	until(tmp1 == 0 and tmp2 == 0)
	return tonumber(str,2)
end

 

使用方法如下：

local tmp1 = 0x52
local tmp2 = 0x01

print(Xor(tmp1,tmp2))  --输出tmp1 异或 tmp2 的操作结果
print(And(tmp1,tmp2))    --输出tmp1 与 tmp2 的操作结果
print(Or(tmp1,tmp2))    --输出tmp1 或 tmp2 的操作结果

加入支持负数的位运算操作： 但是负数和负数位操作出来的显示是个整数

如 And(-8,-5)    结果 ：4294967288  在32位机器上就是 -8

function checkNums( nums )
	local n = nums
	if n >= 0 then
		return n
	else
		n = 0 - n
		n = 0xffffffff - n + 1
	end
	return n
end
function resultCover( n )
	local  num = n
	if num >= 0x80000000 then
		num = num - 0xffffffff - 1
	end
	return num
end

function And(num1,num2)
	local tmp1 = checkNums(num1)
	local tmp2 = checkNums(num2)
	local ret = 0
	local count = 0
	repeat
		local s1 = tmp1 % 2
		local s2 = tmp2 % 2
		if s1 == s2 and s1 == 1 then
			ret = ret + 2^count
		end
		tmp1 = math.modf(tmp1/2)
		tmp2 = math.modf(tmp2/2)
		count = count + 1
	until(tmp1 == 0 and tmp2 == 0)
	return resultCover(ret)
end

function Or(num1,num2)
	local tmp1 = checkNums(num1)
	local tmp2 = checkNums(num2)
	local ret = 0
	local count = 0
	repeat
		local s1 = tmp1 % 2
		local s2 = tmp2 % 2
		if s1 == s2 and s1 == 0 then

		else
			ret = ret + 2^count
		end
		tmp1 = math.modf(tmp1/2)
		tmp2 = math.modf(tmp2/2)
		count = count + 1
	until(tmp1 == 0 and tmp2 == 0)
	return resultCover(ret)
end


function Xor(num1,num2)
	local tmp1 = checkNums(num1)
	local tmp2 = checkNums(num2)
	local ret = 0
	local count = 0
	repeat
		local s1 = tmp1 % 2
		local s2 = tmp2 % 2
		if s1 ~= s2 then
			ret = ret + 2^count
		end
		tmp1 = math.modf(tmp1/2)
		tmp2 = math.modf(tmp2/2)
		count = count + 1
	until(tmp1 == 0 and tmp2 == 0)
	return resultCover(ret)
end

5.3开始自带位操作：

&	按位与
|	按位或
~	按位异或
>>	右移
<<	左移
~	按位非

使用方法：
c = a & b      
c = a | b
c = a ~ b
c = a >> b
c = a << b
c = ~a