使用Java创建rest 服务 通过HTTP请求访问资源

2019独角兽企业重金招聘Python工程师标准>>>

使用jersey创建rest webservice

1 在eclipse中创建动态web工程

2 build jersey jar包

3 创建rest 服务端

package com.kcharf.gis.restws;

import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;

//这里@Path定义了类的层次路径
//指定了资源类提供该服务的URI路径
@Path("UserInfoService")
public class UserInfo {
	//@Get表示方法会处理HTTP get请求
	@GET
	@Path("/name/{i}")//指定资源类提供服务的uri路径
	@Produces(MediaType.TEXT_XML)//资源类方法会产生媒体类型
	//PathParam向Path定义的表达式注入uri参数值
	public String userName(@PathParam("i") String i){
		String name = i;
		return "" + "" + name + "" + "";
	}
}

 

4 创建客户端测试

package com.kcharf.gis.restclient;

 
import javax.ws.rs.core.MediaType;
 
import com.sun.jersey.api.client.Client;
import com.sun.jersey.api.client.ClientResponse;
import com.sun.jersey.api.client.WebResource;
import com.sun.jersey.api.client.config.ClientConfig;
import com.sun.jersey.api.client.config.DefaultClientConfig;
 
/**
* 
* @author pavithra
* 
*/
public class UserInfoClient {
 
public static final String BASE_URI = "http://localhost:8080/restws";
public static final String PATH_NAME = "/UserInfoService/name/";
public static final String PATH_AGE = "/UserInfoService/age/";
 
public static void main(String[] args) {
 
String name = "Pavithra";
int age = 25;
 
ClientConfig config = new DefaultClientConfig();
Client client = Client.create(config);
WebResource resource = client.resource(BASE_URI);
 
WebResource nameResource = resource.path("rest").path(PATH_NAME + name);
System.out.println("Client Response \n"
+ getClientResponse(nameResource));
System.out.println("Response \n" + getResponse(nameResource) + "\n\n");
 
WebResource ageResource = resource.path("rest").path(PATH_AGE + age);
System.out.println("Client Response \n"
+ getClientResponse(ageResource));
System.out.println("Response \n" + getResponse(ageResource));
}
 
/**
* 返回客户端请求。
* 例如：
* GET http://localhost:8080/restws/rest/UserInfoService/name/Pavithra 
* 返回请求结果状态“200 OK”。
*
* @param service
* @return
*/
private static String getClientResponse(WebResource resource) {
return resource.accept(MediaType.TEXT_XML).get(ClientResponse.class)
.toString();
}
 
/**
* 返回请求结果XML
* 例如：Pavithra 
* 
* @param service
* @return
*/
private static String getResponse(WebResource resource) {
return resource.accept(MediaType.TEXT_XML).get(String.class);
}

 

5 部署web.xml到WEB-INF下

 
 
RESTfulWS 
 
Jersey REST Service 
com.sun.jersey.spi.container.servlet.ServletContainer 
 
com.sun.jersey.config.property.packages 
com.kcharf.gis.restws 
 
1 
 
 
Jersey REST Service 
/rest/* 
 

 

 

 

转载于:https://my.oschina.net/yonguil/blog/388322