获取MSSQL数据字典的SQL语句

CREATE VIEW dbo.vw_db_dictionary AS SELECT TOP 100 PERCENT dbo.sysobjects.name AS table_name, dbo.sysproperties.[value] AS table_desc, dbo.syscolumns.name AS field, properties.[value] AS field_desc, dbo.systypes.name AS field_type, dbo.syscolumns.length AS field_size, ISNULL(COLUMNPROPERTY(dbo.syscolumns.id, dbo.syscolumns.name, 'Scale'), 0) AS field_precision, dbo.syscolumns.isnullable AS nullable, CASE WHEN syscomments.text IS NULL THEN '' ELSE syscomments.text END AS default_value, CASE WHEN COLUMNPROPERTY(syscolumns.id, syscolumns.name, 'IsIdentity') = 1 THEN '√' ELSE '' END AS is_identity, CASE WHEN EXISTS (SELECT 1 FROM sysobjects WHERE xtype = 'PK' AND name IN (SELECT name FROM sysindexes WHERE indid IN (SELECT indid FROM sysindexkeys WHERE id = syscolumns.id AND colid = syscolumns.colid))) THEN '√' ELSE '' END AS is_key FROM dbo.syscolumns INNER JOIN dbo.sysobjects ON dbo.sysobjects.id = dbo.syscolumns.id INNER JOIN dbo.systypes ON dbo.syscolumns.xtype = dbo.systypes.xtype LEFT OUTER JOIN dbo.sysproperties properties ON dbo.syscolumns.id = properties.id AND dbo.syscolumns.colid = properties.smallid LEFT OUTER JOIN dbo.sysproperties ON dbo.sysobjects.id = dbo.sysproperties.id AND dbo.sysproperties.smallid = 0 LEFT OUTER JOIN dbo.syscomments ON dbo.syscolumns.cdefault = dbo.syscomments.id WHERE (dbo.sysobjects.xtype = 'U') ORDER BY dbo.sysobjects.name

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