PAT_B_1080_C++(25分)

看到25分的就放弃Java吧，铁定有超时的

#include 
#include 
#include
#include 
#include 
#include 
using namespace std;
struct node {
    string name;
    int gp, gm, gf, g;
};
map<string, int> idx;
vector<node> v, ans;
bool cmp(node a, node b) {
    if (a.g != b.g)    return a.g > b.g;
    else return a.name < b.name;
}
int main() {
    int p, m, n, score, count = 1;//count作为编号
    scanf("%d%d%d", &p, &m, &n);
    string s;
    for (int i = 0; i < p; i++) {
        cin >> s >> score;
        if (score >= 200) {//把编程分数低于200的过滤掉
            idx[s] = count++;
            v.push_back(node{ s, score, -1, -1, 0 });
            //最新入容器的其他分数都是-1,方便后面输出
        }
    }
    for (int i = 0; i < m; i++) {
        cin >> s >> score;
        if (idx[s] != 0) {
            v[idx[s] - 1].gm = score;
        }
    }
    for (int i = 0; i < n; i++) {
        cin >> s >> score;
        if (idx[s] != 0) {
            int temp = idx[s] - 1;
            v[temp].gf = v[temp].g = score;//这里道理同上,这样写的方式确实比较省事
            if (v[temp].gm > v[temp].gf) {
                v[temp].g = int(0.4 * v[temp].gm + 0.6 * v[temp].gf + 0.5);
            }
        }
    }
    for (int i = 0; i < v.size(); i++) {
        if (v[i].g >= 60) {
            ans.push_back(v[i]);
        }
    }
    sort(ans.begin(), ans.end(), cmp);
    for (int i = 0; i < ans.size(); i++) {
        printf("%s %d %d %d %d\n", ans[i].name.c_str(), ans[i].gp, ans[i].gm, ans[i].gf, ans[i].g);
    }
}