如何将char转换为String？

本文翻译自：How to convert a char to a String?

I have a char and I need a String . 我有一个char ，我需要一个String 。 How do I convert from one to the other? 我如何从一个转换为另一个？

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#1楼

参考：https://stackoom.com/question/YI1E/如何将char转换为String

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#2楼

Nice question. 好问题。 I've got of the following five 6 methods to do it. 我有以下 五种 方法可以做到这一点。

1. String stringValueOf = String.valueOf('c'); // most efficient

2. String stringValueOfCharArray = String.valueOf(new char[]{x});

3. String characterToString = Character.toString('c');

4. String characterObjectToString = new Character('c').toString();

   // Although this method seems very simple, 
   // this is less efficient because the concatenation
   // expands to new StringBuilder().append(x).append("").toString();
5. String concatBlankString = 'c' + "";

6. String fromCharArray = new String(new char[]{x});

Note: Character.toString(char) returns String.valueOf(char) . 注意： Character.toString（char）返回String.valueOf（char） 。 So effectively both are same. 所以两者都是一样的。

String.valueOf(char[] value) invokes new String(char[] value) , which in turn sets the value char array. String.valueOf(char[] value)调用new String(char[] value) ，后者又设置value char数组。

public String(char value[]) {
    this.value = Arrays.copyOf(value, value.length);
}

On the other hand String.valueOf(char value) invokes the following package private constructor. 另一方面， String.valueOf(char value)调用以下包私有构造函数。

String(char[] value, boolean share) {
    // assert share : "unshared not supported";
    this.value = value;
}

Source code from String.java in Java 8 source code Java 8源代码中 String.java 源代码

Hence String.valueOf(char) seems to be most efficient method, in terms of both memory and speed, for converting char to String . 因此，就内存和速度而言， String.valueOf(char)似乎是将char转换为String最有效方法。

1. How to convert primitive char to String in Java 如何在Java中将原始char转换为String
2. How to convert Char to String in Java with Example 如何使用Example将Java中的Char转换为String

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#3楼

Below are various ways to convert to char c to String s (in decreasing order of speed and efficiency) 下面是转换为char c到String s的各种方法（按速度和效率的降序排列）

char c = 'a';
String s = String.valueOf(c);             // fastest + memory efficient
String s = Character.toString(c);
String s = new String(new char[]{c});
String s = String.valueOf(new char[]{c});
String s = new Character(c).toString();
String s = "" + c;                        // slowest + memory inefficient

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#4楼

We have various ways to convert a char to String . 我们有各种方法将char转换为String 。 One way is to make use of static method toString() in Character class: 一种方法是在Character类中使用静态方法toString() ：

char ch = 'I'; 
String str1 = Character.toString(ch);

Actually this toString method internally makes use of valueOf method from String class which makes use of char array: 实际上这个toString方法在内部使用了String类中的valueOf方法，该方法使用了char数组：

public static String toString(char c) {
    return String.valueOf(c);
}

So second way is to use this directly: 所以第二种方法是直接使用它：

String str2 = String.valueOf(ch);

This valueOf method in String class makes use of char array: String类中的valueOf方法使用char数组：

public static String valueOf(char c) {
        char data[] = {c};
        return new String(data, true);
}

So the third way is to make use of an anonymous array to wrap a single character and then passing it to String constructor: 所以第三种方法是使用匿名数组来包装单个字符，然后将其传递给String构造函数：

String str4 = new String(new char[]{ch});

The fourth way is to make use of concatenation: 第四种方法是使用串联：

String str3 = "" + ch;

This will actually make use of append method from StringBuilder class which is actually preferred when we are doing concatenation in a loop. 这实际上将使用StringBuilder类中的append方法，当我们在循环中进行连接时，它实际上是首选的。

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#5楼

Here are a few methods, in no particular order: 以下是一些方法，没有特别的顺序：

char c = 'c';

String s = Character.toString(c); // Most efficient way

s = new Character(c).toString(); // Same as above except new Character objects needs to be garbage-collected

s = c + ""; // Least efficient and most memory-inefficient, but common amongst beginners because of its simplicity

s = String.valueOf(c); // Also quite common

s = String.format("%c", c); // Not common

Formatter formatter = new Formatter();
s = formatter.format("%c", c).toString(); // Same as above
formatter.close();

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#6楼

I've tried the suggestions but ended up implementing it as follows 我已经尝试了这些建议但最终实现如下

editView.setFilters(new InputFilter[]{new InputFilter()
        {
            @Override
            public CharSequence filter(CharSequence source, int start, int end,
                                       Spanned dest, int dstart, int dend)
            {
                String prefix = "http://";

                //make sure our prefix is visible
                String destination = dest.toString();

                //Check If we already have our prefix - make sure it doesn't
                //get deleted
                if (destination.startsWith(prefix) && (dstart <= prefix.length() - 1))
                {
                    //Yep - our prefix gets modified - try preventing it.
                    int newEnd = (dend >= prefix.length()) ? dend : prefix.length();

                    SpannableStringBuilder builder = new SpannableStringBuilder(
                            destination.substring(dstart, newEnd));
                    builder.append(source);
                    if (source instanceof Spanned)
                    {
                        TextUtils.copySpansFrom(
                                (Spanned) source, 0, source.length(), null, builder, newEnd);
                    }

                    return builder;
                }
                else
                {
                    //Accept original replacement (by returning null)
                    return null;
                }
            }
        }});