使用Java模拟登录

运行环境

本次开发在Windos上进行，运行环境为：

java 11.0.2 2019-01-15 LTS
Java(TM) SE Runtime Environment 18.9 (build 11.0.2+9-LTS)
Java HotSpot(TM) 64-Bit Server VM 18.9 (build 11.0.2+9-LTS, mixed mode)

步骤

浏览器阶段

本次模拟网站：https://www.bbaaz.com
其登录界面网址为：https://www.bbaaz.com/member.php?mod=logging&action=login

先使用浏览器打开，输入用户名、密码，然后F12打开Dev Tools，选择Network选项卡，注意勾选Preserve log，不然可能的情况是，你点了登录，由于package太多的原因，或者跳转新页面，关键的包已经舍弃掉了。
找到关键包，如下图，可以看到很多信息。

从package中可以获取到：

Request URL: https://www.bbaaz.com/member.php?mod=logging&action=login&loginsubmit=yes&loginhash=Lm0Hi&inajax=1

Set-Cookie:xxxxx

Form Data
formhash: xxxxx
referer: https://www.bbaaz.com/
loginfield: username
username: xxxxx
password: xxxxx
questionid: 0
answer: 

仔细观察，发现了什么，首先，Request URL带有了一个loginhash，再Form Data中带有了formhash，这些应该是防止非法登录的，那么这些数据哪里来的呢？经过注销，重新打开登陆界面，分析登录界面，可以得知这些信息，都是原登录界面的隐藏信息。

思路

那么我们的思路就是，首先，打开登录界面，从登录界面获取两个Hash值，再打开一个能存放Cookie的Request，给登录URL发送表单，记录返回的Cookie，再打开别的页面的时候，就可以通过Cookie进行访问。

编码

注意，以下编码为了便于阅读，进行了修改，编码习惯并不好，请不要学习编码习惯。

final String loginURL = "https://www.bbaaz.com/member.php?mod=logging&action=login";
String query = "&loginsubmit=yes&frommessage&loginhash=xxx&inajax=1";
String form = "formhash=xxx&referer=https://www.bbaaz.com/&loginfield=username&username=xxxx&password=xxxx&questionid=0&answer=";
final String headerAgent = "User-Agent";
final String headerAgentArg = "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/71.0.3562.0 Safari/537.36";
byte [] buffer;
byte [] all;
int length;
ArrayList byteList;
ArrayList byteLength;
int totalLength = 0;
String [] content = null;
String formhash, suffix; //两个Hash值

try {
	// 在刚开始就使用CookieManager的原因是，经过测试，在打开登录界面的时候，服务器就会向客户端发送3个Cookie，这些Cookie同样有验证作用，如果不带上，那么登录的时候，服务器会返回，含有非法字符，无法登录
	CookieManager manager = new CookieManager();
	manager.setCookiePolicy(CookiePolicy.ACCEPT_ORIGINAL_SERVER);
	CookieHandler.setDefault(manager);
	HttpURLConnection httpURLConnection = (HttpURLConnection) (new URL(loginURL).openConnection());
	httpURLConnection.setRequestMethod("GET");
	httpURLConnection.setRequestProperty(headerAgent, headerAgentArg);
	httpURLConnection.connect();
	if(httpURLConnection.getResponseCode() == 200) {
		InputStream inputStream = httpURLConnection.getInputStream();
		buffer = new byte[1024];
		byteList = new ArrayList<>();
		byteLength = new ArrayList<>();
		while( (length = inputStream.read(buffer)) != -1 ) {
			byteList.add(buffer);
			byteLength.add(length);
            totalLength += length;
           	buffer = new byte[1024];
		}
		httpURLConnection.disconnect();
		all = new byte[totalLength];
		totalLength = 0;
		while(byteList.size() != 0) {
			System.arraycopy(byteList.get(0), 0, all, totalLength, byteLength.get(0));
			totalLength += byteLength.get(0);
			byteList.remove(0);
			byteLength.remove(0);
		}
		// 通过第一次打开的页面获取Hash值
		content = new String(all, "UTF-8").split("
", 2)[0];
		// 第二次获取网页，会自动携带Cookie信息
		httpURLConnection = (HttpURLConnection) (new URL(loginURL + query.replace("xxx", suffix)).openConnection());
		httpURLConnection.setRequestMethod("POST");
		httpURLConnection.setRequestProperty(headerAgent, headerAgentArg);
		httpURLConnection.setDoOutput(true);
		httpURLConnection.connect();
		httpURLConnection.getOutputStream().write(form.replace("xxx", formhash).getBytes("UTF-8"));
		inputStream = httpURLConnection.getInputStream();
		buffer = new byte[1024];
		byteList = new ArrayList<>();
		byteLength = new ArrayList<>();
		totalLength = 0;
		while( (length = inputStream.read(buffer)) != -1 ) {
			byteList.add(buffer);
			byteLength.add(length);
			totalLength += length;
			buffer = new byte[1024];
		}
		httpURLConnection.disconnect();
		all = new byte[totalLength];
		totalLength = 0;
		while(byteList.size() != 0) {
			System.arraycopy(byteList.get(0), 0, all, totalLength, byteLength.get(0));
			totalLength += byteLength.get(0);
			byteList.remove(0);
			byteLength.remove(0);
		}
		new String(all, "UTF-8"); // 查看该页面信息，登录成功
		all = null;
	}
} catch (Exception e) {
	e.printStackTrace();
}

经测试，使用该方法，成功模拟登录。

使用python模拟登录

https://blog.csdn.net/yancr/article/details/88748521