sql 中的 indexOf 与 lastIndexOf

DECLARE @Name NVARCHAR (50)

SET @Name = '12345.67890ABCDE.FGHIJKLMNOPQRSTUVWXYZTest'

 

DECLARE @Position INT

 

--sql first indexof

SET @Position = CHARINDEX('.', @Name);

SELECT SUBSTRING (@Name, @Position+1,LEN(@Name)-@Position)

 

--sql last indexof

SET @Position =  LEN(@Name) - CHARINDEX('.', REVERSE(@Name)) + 1

SELECT SUBSTRING (@Name, 0, @Position)