2018CCPC吉林赛区（重现赛）- 1001 The Fool

Problem Description

The Fool is numbered 0 – the number of unlimited potential –and therefore does not have a specific place in the sequence of the Tarot cards. The Fool can be placed either at the beginning of the Major Arcana or at the end. The Major Arcana is often considered as the Fool’s journey through life and as such, he is
ever present and therefore needs no number.

Given n ∈ N+ , print the parity of

∑i=1N [ni ]，

where [x] = max a (a∈Z,a≤x)

Input

The first line of the input contains one integer T ≤ 100, denoting the number of testcases. Then T testcases follow.
In each of the T testcases, there is a positive number n ≤ 109 .

Output

For each testcase, print a single line starting with “Case i : ”(i indicates the case number) and then “even” or “odd”, separated with a single space.

Sample Input

3

1

10000

100000000

Sample Output

Case 1: odd

Case 2: even

Case 3: even

【题解】

打个表找个规律就行

#include 
#include 
#include 
#include 
using namespace std;
int main()
{
     int t,n;
    scanf("%d",&t);
    for(int k=1;k<=t;k++){
        scanf("%d",&n);
        int ans=sqrt(n);
        if(ans%2==1) printf("Case %d: odd\n",k);
        else printf("Case %d: even\n",k);
    }
    return 0;
}