Captain Flint and Crew Recruitment CodeForces - 1388A rat800

Despite his bad reputation, Captain Flint is a friendly person (at least, friendly to animals). Now Captain Flint is searching worthy sailors to join his new crew (solely for peaceful purposes). A sailor is considered as worthy if he can solve Flint’s task.

Recently, out of blue Captain Flint has been interested in math and even defined a new class of integers. Let’s define a positive integer x as nearly prime if it can be represented as p⋅q, where 1

Captain Flint guessed an integer n and asked you: can you represent it as the sum of 4 different positive integers where at least 3 of them should be nearly prime.

Uncle Bogdan easily solved the task and joined the crew. Can you do the same?

Input
The first line contains a single integer t (1≤t≤1000) — the number of test cases.

Next t lines contain test cases — one per line. The first and only line of each test case contains the single integer n (1≤n≤2⋅105) — the number Flint guessed.

Output
For each test case print:

YES and 4 different positive integers such that at least 3 of them are nearly prime and their sum is equal to n (if there are multiple answers print any of them);
NO if there is no way to represent n as the sum of 4 different positive integers where at least 3 of them are nearly prime.
You can print each character of YES or NO in any case.
Example
Input
7
7
23
31
36
44
100
258
Output
NO
NO
YES
14 10 6 1
YES
5 6 10 15
YES
6 7 10 21
YES
2 10 33 55
YES
10 21 221 6
Note
In the first and second test cases, it can be proven that there are no four different positive integers such that at least three of them are nearly prime.

In the third test case, n=31=2⋅7+2⋅5+2⋅3+1: integers 14, 10, 6 are nearly prime.

In the fourth test case, n=36=5+2⋅3+2⋅5+3⋅5: integers 6, 10, 15 are nearly prime.

In the fifth test case, n=44=2⋅3+7+2⋅5+3⋅7: integers 6, 10, 21 are nearly prime.

In the sixth test case, n=100=2+2⋅5+3⋅11+5⋅11: integers 10, 33, 55 are nearly prime.

In the seventh test case, n=258=2⋅5+3⋅7+13⋅17+2⋅3: integers 10, 21, 221, 6 are nearly prime.
用最小的互质数6 10 15 来代替前三个数字，记得在重复使用是特殊判断一下

#include
#include
#include
#include
#include
#include
#include
using namespace std;
#define inf 0x3f3f3f3f
const int maxn = 3e5+10;
int n;
int main()
{
    int t;
    scanf("%d",&t);
    while(t--){
        scanf("%d",&n);
        if(n<=30)
            printf("NO\n");
        else if(n==36||n==40||n==44)
            printf("YES\n 6 10 15 %d\n",n-31);
        else
            printf("YES\n 6 10 14 %d\n",n-30);
    }
    system("pause");
	return 0;
}