AtCoder Beginner Contest 105 C - Base -2 Number

Time Limit: 2 sec / Memory Limit: 1024 MB

Score : 300300 points

Problem Statement

Given an integer NN, find the base −2−2 representation of NN.

Here, SS is the base −2−2 representation of NN when the following are all satisfied:

• SS is a string consisting of 0 and 1.
• Unless S=S= 0, the initial character of SS is 1.
• Let S=SkSk−1...S0S=SkSk−1...S0, then S0×(−2)0+S1×(−2)1+...+Sk×(−2)k=NS0×(−2)0+S1×(−2)1+...+Sk×(−2)k=N.

It can be proved that, for any integer MM, the base −2−2 representation of MM is uniquely determined.

Constraints

• Every value in input is integer.
• −109≤N≤109−109≤N≤109

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Input

Input is given from Standard Input in the following format:

NN

Output

Print the base −2−2 representation of NN.

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Sample Input 1

-9

Sample Output 1

1011

As (−2)0+(−2)1+(−2)3=1+(−2)+(−8)=−9(−2)0+(−2)1+(−2)3=1+(−2)+(−8)=−9, 1011 is the base −2−2 representation of −9−9.

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Sample Input 2

123456789

Sample Output 2

11000101011001101110100010101

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Sample Input 3

0

Sample Output 3

0

 

#include
#include
using namespace std;
int c[2]={0,1};

int main()
{
	int n,i=0,k,t;
	int s[3000]={0};
	cin>>n;
	if(n==0)
	{
		cout<<"0"<=1;i--)
		cout<

 

总结：开始想开个大数组一位一位算过去= =，后来仔细一想发现只要像做二进制题一样，模拟-2进制运算就可以轻松解出了。