python 的numpy库中的mean()函数用法

1. mean() 函数定义：

numpy. mean ( a,  axis=None,  dtype=None,  out=None,  keepdims= ) [source]

Compute the arithmetic mean along the specified axis.

Returns the average of the array elements. The average is taken over the flattened array by default, otherwise over the specified axis. float64intermediate and return values are used for integer inputs.

Parameters:

a : array_like Array containing numbers whose mean is desired. If a is not an array, a conversion is attempted. axis : None or int or tuple of ints, optional Axis or axes along which the means are computed. The default is to compute the mean of the flattened array. New in version 1.7.0. If this is a tuple of ints, a mean is performed over multiple axes, instead of a single axis or all the axes as before. dtype : data-type, optional Type to use in computing the mean. For integer inputs, the default is float64; for floating point inputs, it is the same as the input dtype. out : ndarray, optional Alternate output array in which to place the result. The default is None; if provided, it must have the same shape as the expected output, but the type will be cast if necessary. See doc.ufuncs for details. keepdims : bool, optional If this is set to True, the axes which are reduced are left in the result as dimensions with size one. With this option, the result will broadcast correctly against the input array. If the default value is passed, then keepdims will not be passed through to the mean method of sub-classes of ndarray, however any non-default value will be. If the sub-classes sum method does not implement keepdims any exceptions will be raised.

Returns:

m : ndarray, see dtype parameter above If out=None, returns a new array containing the mean values, otherwise a reference to the output array is returned.

2   mean()函数功能：求取均值

经常操作的参数为axis，以m * n矩阵举例：

axis 不设置值，对 m*n 个数求均值，返回一个实数

axis = 0：压缩行，对各列求均值，返回 1* n 矩阵

axis =1 ：压缩列，对各行求均值，返回 m *1 矩阵

举例：

>>>  import numpy as np

>>> num1 = np.array([[1,2,3],[2,3,4],[3,4,5],[4,5,6]])
>>> now2 = np.mat(num1)
>>> now2
matrix([[1, 2, 3],
        [2, 3, 4],
        [3, 4, 5],
        [4, 5, 6]])

>>> np.mean(now2) # 对所有元素求均值
3.5

>>> np.mean(now2,0) # 压缩行，对各列求均值
matrix([[ 2.5,  3.5,  4.5]])

>>> np.mean(now2,1) # 压缩列，对各行求均值
matrix([[ 2.],
        [ 3.],
        [ 4.],
        [ 5.]])