魔法森林

LCT
a排序后做b的kruskal
splay维护最大边的位置，若当前大，不加，否则cut，加边

# include 
# include 
# include 
# include 
# include 
# define IL inline
# define RG register
# define Fill(a, b) memset(a, b, sizeof(a))
using namespace std;
typedef long long ll;

IL ll Read(){
    RG char c = getchar(); RG ll x = 0, z = 1;
    for(; c < '0' || c > '9'; c = getchar()) z = c == '-' ? -1 : 1;
    for(; c >= '0' && c <= '9'; c = getchar()) x = (x << 1) + (x << 3) + c - '0';
    return x * z;
}

const int MAXN(2e5 + 10);
int S[MAXN], n, m, ans = 1 << 30;
struct Edge{
    int u, v, a, b;
    IL bool operator <(RG Edge B) const{  return a < B.a;  }
} edge[MAXN];
struct Tree{  int fa, ch[2], rev, maxb;  } t[MAXN];

IL bool Isroot(RG int x){  return t[t[x].fa].ch[0] != x && t[t[x].fa].ch[1] != x;  }

IL void Update(RG int x){
    t[x].maxb = x;
    if(edge[t[t[x].ch[0]].maxb].b > edge[t[x].maxb].b) t[x].maxb = t[t[x].ch[0]].maxb;
    if(edge[t[t[x].ch[1]].maxb].b > edge[t[x].maxb].b) t[x].maxb = t[t[x].ch[1]].maxb;
}

IL void Pushdown(RG int x){
    if(!t[x].rev) return;
    swap(t[x].ch[0], t[x].ch[1]);
    t[x].rev = 0; t[t[x].ch[0]].rev ^= 1; t[t[x].ch[1]].rev ^= 1;
}

IL bool Son(RG int x){  return t[t[x].fa].ch[1] == x;  }

IL void Rot(RG int x){
    RG int y = t[x].fa, z = t[y].fa, c = Son(x);
    if(!Isroot(y)) t[z].ch[Son(y)] = x; t[x].fa = z;
    t[y].ch[c] = t[x].ch[!c]; t[t[y].ch[c]].fa = y;
    t[x].ch[!c] = y; t[y].fa = x;
    Update(y);
}

IL void Splay(RG int x){
    RG int top = 0; S[++top] = x;
    for(RG int y = x; !Isroot(y); y = t[y].fa) S[++top] = t[y].fa;
    while(top) Pushdown(S[top--]);
    for(RG int y = t[x].fa; !Isroot(x); Rot(x), y = t[x].fa)
        if(!Isroot(y)) Son(x) ^ Son(y) ? Rot(x) : Rot(y);
    Update(x);
}

IL void Access(RG int x){  for(RG int y = 0; x; y = x, x = t[x].fa) Splay(x), t[x].ch[1] = y, Update(x);  }

IL void Makeroot(RG int x){  Access(x); Splay(x); t[x].rev ^= 1;  }

IL int Findroot(RG int x){  Access(x); Splay(x); while(t[x].ch[0]) x = t[x].ch[0]; return x;  }

IL void Split(RG int x, RG int y){  Makeroot(x); Access(y); Splay(y);   }

IL void Link(RG int x, RG int y){  Makeroot(x); t[x].fa = y;  }

IL void Cut(RG int x, RG int y){  Split(x, y); t[x].fa = t[y].ch[0] = 0;  }

IL int Query(RG int u, RG int v){  Split(u, v); return t[v].maxb;  }

int main(RG int argc, RG char* argv[]){
    n = Read(); m = Read();
    for(RG int i = 1; i <= m; i++) edge[i] = (Edge){Read(), Read(), Read(), Read()};
    sort(edge + 1, edge + m + 1);
    for(RG int i = 1; i <= m; i++){
        RG int u = edge[i].u + m, v = edge[i].v + m;
        if(Findroot(u) != Findroot(v)) Link(u, i), Link(v, i);
        else{
            RG int mx = Query(u, v);
            if(edge[i].b < edge[mx].b) Cut(edge[mx].u + m, mx), Cut(edge[mx].v + m, mx), Link(u, i), Link(v, i);
        }
        if(Findroot(1 + m) == Findroot(n + m)) ans = min(ans, edge[i].a + edge[Query(1 + m, n + m)].b);
    }
    printf("%d\n", ans != (1 << 30) ? ans : -1);
    return 0;
}

转载于:https://www.cnblogs.com/cjoieryl/p/8206377.html