1003Emergency(25)

正式入坑 PAT ，这道题我的解是东拼西凑吧，用了 http://blog.csdn.net/apie_czx/article/details/45310675  这个大佬的思路，然后刘汝佳的模板

在此奉上代码

#include

#include

#include

#include

using namespace std;

const int maxn=500+5;

const int INF=100000000;

struct E{

    int from,to,weight;

    E(int from,int to,int weight):from(from)

     ,to(to),weight(weight){}

   bool operator <(const E &rhs)const{

       return this->weight>rhs.weight;

    }

};

struct H{

    int u,dis;

    H(int u,int dis):

        u(u),dis(dis){}

   bool operator <(const H &rhs) const{

        return this->dis>rhs.dis;

    }

};

vector<int> G[maxn];

vector<E> edges;

int dis[maxn];

int mark[maxn];

int paths[maxn];

int nums[maxn];

int all_nums[maxn];

void addEdge(int from,int to,int weight)

{

    edges.push_back(E(from,to,weight));

    int ss=edges.size();

    G[from].push_back(ss-1);

}

int main()

{

#ifdef LOCAL

    freopen("data.in","r",stdin);

#endif

    int n,m,from,to;

    scanf("%d%d%d%d",&n,&m,&from,&to);

        edges.clear();

        for(int i=0;i<n;i++)

        {

            G[i].clear();

            dis[i]=INF;

            mark[i]=0;

            paths[i]=0;

           scanf("%d",&nums[i]);

            all_nums[i]=0;

        }

        int c1,c2,w;

        for(int i=0;i<m;i++)

        {

            scanf("%d%d%d",&c1,&c2,&w);

            addEdge(c1,c2,w);

            addEdge(c2,c1,w);

        }

        dis[from]=0;

        paths[from]=1;

        all_nums[from]=nums[from];

        priority_queue<H> qq;

        qq.push(H(from,dis[from]));

        while(!qq.empty())

        {

            H h= qq.top();

            qq.pop();

            int u=h.u;

            if(mark[u])

                continue;

            mark[u]=true;

            int old_d=h.dis;

            for(int i=0;i<G[u].size();i++)

            {

                E new_E=edges[G[u][i]];

                if(dis[new_E.to]>new_E.weight+old_d )

                {

                    paths[new_E.to]=paths[u];

                    dis[new_E.to]=new_E.weight+old_d;

                    all_nums[new_E.to]=nums[new_E.to]+all_nums[u];

                }

                else if(dis[new_E.to]==new_E.weight+old_d )

                {

                    paths[new_E.to]+=paths[u];

                    if(all_nums[new_E.to]<all_nums[u]+nums[new_E.to])

                    {

                        all_nums[new_E.to]=all_nums[u]+nums[new_E.to];

                    }

                }

                qq.push(H(new_E.to,dis[new_E.to]));

            }

        }//while

        cout<<paths[to]<<" "<<all_nums[to]<<endl;

    return 0;

}

// priority_queue qq;

// qq.push(E(2,3,4));

// qq.push(E(1,2,2));

// qq.push(E(4,1,3));

// while(!qq.empty())

// {

//     cout<

//     qq.pop();

// }