Bad Hair Day

题目描述

Some of Farmer John's N cows (1 ≤ N ≤ 80,000) are having a bad hair day! Since each cow is self-conscious about her messy hairstyle, FJ wants to count the number of other cows that can see the top of other cows' heads.
 
Each cow i has a specified height hi (1 ≤ hi ≤ 1,000,000,000) and is standing in a line of cows all facing east (to the right in our diagrams). Therefore, cow i can see the tops of the heads of cows in front of her (namely cows i+1, i+2, and so on), for as long as these cows are strictly shorter than cow i.

Consider this example:
　　　　　　　　＝
＝　　　　　　　＝
＝　　　＝　　　＝　　　　　　　Cows facing right－－＞
＝　　　＝　　　＝
＝　＝　＝　＝　＝
＝　＝　＝　＝　＝　＝
１　２　３　４　５　６
 
Cow#1 can see the hairstyle of cows #2, 3, 4
Cow#2 can see no cow's hairstyle
Cow#3 can see the hairstyle of cow #4
Cow#4 can see no cow's hairstyle
Cow#5 can see the hairstyle of cow 6
Cow#6 can see no cows at all!

Let ci denote the number of cows whose hairstyle is visible from cow i; please compute the sum of c1 through cN.For this example, the desired is answer 3 + 0 + 1 + 0 + 1 + 0 = 5.

输入

Line 1: The number of cows, N.
Lines 2..N+1: Line i+1 contains a single integer that is the height of cow i.

输出

Line 1: A single integer that is the sum of c ₁ through c _N.

示例输入

6
10
3
7
4
12
2

示例输出

5

 

1. #include   
2. #include   
3. using namespace std;  
4. int main()  
5. {  
6.     long long int a[80004];  
7.     int i,k,j,m,n,l;  
8.     long long int sum=0;  
9.     cin>>n;  
10.     for(i=0;i
11.     {  
12.        cin>>a[i];  
13.     }  
14.     for(i=0;i
15.     {  
16.         for(j=i+1;j
17.         {  
18.             if(a[i]>a[j])  
19.                 {  
20.                     sum=sum+1;  
21.                 }  
22.             else  
23.             {  
24.                 break;  
25.             }  
26.         }  
27.     }  
28.    cout<
29.     return 0;  
30. }