将字符串s1中任何与字符串s2匹配的字符都删去，存放于一个新的字符串s3中

 

//编写函数squeeze(s1,s2)，将字符串s1中任何与字符串s2匹配的字符都删去

#include
#include

char *squeeze(char*s1,char*s2);
char s1[];
char s2[];
char *s3;

int main()
{
 int n=0;
 s1="zhangchaozhang";
 s2="chao";
 printf("s1:%s\n",s1);printf("s2:%s\n",s2);
 s3=squeeze(s1,s2);
 printf("delete characters in s1 that matches s2 get s3:\n%s",s3);
}

char *squeeze(char*s1,char*s2)
{
 int i,j,len1,len2;
 int compare=1;//默认为1
 int k=0;
 char s3[100];
 len1=strlen(s1);len2=strlen(s2);
 for(i=0,k=0;i  {
  if(s1[i]==s2[0])//s1遇到与s2第一个字符相等的字符，进入判断
  {
   for(j=i+1;(j    {
    if(s1[j]==s2[j-i])
     compare=0;
    else
    {
     compare=1;//有不相等的字符
     break;
    }
   }
  }
  if(!compare)//s1中有和s2匹配的字符串
  {
   s3[k]=s1[i+len2];
  }
  else
   s3[k]=s1[i];
 }
 s3[k]='\0';
 return s3;
}