有序单链表的合并-递归方式

有序单链表的合并

#include 
#include "stdlib.h"
typedef struct node 
{
	int data;
	struct node *next;
}node;

struct node *create()
{
	int i =0;
	struct  node *head, *p, *q;
	int x = 0;
	head = (struct node *)malloc(sizeof(struct node));
	while(1)
	{
		printf("Please input the data:");
		scanf("%d" , &x);
		printf("%d\n",x);
		if(x == 0)
		 	break;
		p =(struct node *)malloc(sizeof(struct node));
		p->data = x;

		if(++i == 1)
		{
			head->next = p;
		}
		else 
		{
			q->next = p;
		}
		q = p;
	}
	q->next = NULL;
	return head;
}

struct node *MergeRecursive(struct node *head1,struct node *head2)
{
	struct node *head  = NULL;
	if(head1 == NULL)
	{
		return head2;
	}
	if(head2 == NULL)
	{
		return head1;
	}
	if(head1->data < head2->data)
	{
		head = head1;
		head->next = MergeRecursive(head1->next,head2);
	}
	else
	{
		head = head2;
		head->next = MergeRecursive(head1,head2->next);
	}
	return head;
}
void print(struct node *head)
{
	struct node *p;
	int index = 0;
	if(head->next == NULL)
	{
		printf("Link is empty!\n");
		return ;
	}
	p =  head->next ;
	while(p != NULL )
	{
		printf("the %dth node is :%d\n",++index,p->data);
		p = p->next; 
	}
}

int main()
{
   /* 我的第一个 C 程序 */
    struct node *head1 = create();
	struct node *head2 = create();
	struct node *head = MergeRecursive(head1,head2);
	print(head);
   return 0;
}

Please input the data:1
Please input the data:4
Please input the data:6
Please input the data:8
Please input the data:0
Please input the data:3
Please input the data:6
Please input the data:7
Please input the data:8
Please input the data:9
Please input the data:0
the 1th node is :0
the 2th node is :1
the 3th node is :3
the 4th node is :4
the 5th node is :6
the 6th node is :6
the 7th node is :7
the 8th node is :8
the 9th node is :8
the 10th node is :9
注意一点：
在菜鸟工具中scanf的使用方法：

scanf输入元素必须用空格分隔开来。