python 构造程序逻辑

1. 寻找“水仙花数”。

   找出100~999之间的所有水仙花数
   水仙花数是各位立方和等于这个数本身的数
   for num in range(100, 1000):
       low = num % 10
       mid = num // 10 % 10
       high = num // 100
       if num == low ** 3 + mid ** 3 + high ** 3:
           print(num)

    

2. 寻找“完美数”。

   import time
   import math
   
   for num in range(1, 10000):
       sum = 0
       for factor in range(1, int(math.sqrt(num)) + 1):
           if num % factor == 0:
               sum += factor
               if factor > 1 and num / factor != factor:
                   sum += num / factor
       if sum == num:
           print(num)

    

3. “百钱百鸡”问题。

   for x in range(0, 20):
       for y in range(0, 33):
           z = 100 - x - y
           if 5 * x + 3 * y + z / 3 == 100:
               print('公鸡: %d只, 母鸡: %d只, 小鸡: %d只' % (x, y, z))

    

4. 生成“斐波拉切数列”。

   a = 0
   b = 1
   for _ in range(20):
       a, b = b, a + b
       print(a, end=' ')

    

5. Craps赌博游戏。

   from random import randint
   
   money = 1000
   while money > 0:
       print('你的总资产为:', money)
       needs_go_on = False
       while True:
           debt = int(input('请下注: '))
           if debt > 0 and debt <= money:
               break
       first = randint(1, 6) + randint(1, 6)
       print('玩家摇出了%d点' % first)
       if first == 7 or first == 11:
           print('玩家胜!')
           money += debt
       elif first == 2 or first == 3 or first == 12:
           print('庄家胜!')
           money -= debt
       else:
           needs_go_on = True
   
       while needs_go_on:
           current = randint(1, 6) + randint(1, 6)
           print('玩家摇出了%d点' % current)
           if current == 7:
               print('庄家胜')
               money -= debt
               needs_go_on = False
           elif current == first:
               print('玩家胜')
               money += debt
               needs_go_on = False
   
   print('你破产了, 游戏结束!')

   """
   	判断输入的正整数是不是回文数
   	回文数是指将一个正整数从左往右排列和从右往左排列值一样的数
   	"""
   	num = int(input('请输入一个正整数: '))
   	temp = num
   	num2 = 0
   	while temp > 0:
   	num2 *= 10
   	num2 += temp % 10
   	temp //= 10
   	if num == num2:
   	print('%d是回文数' % num)
   	else:
   	print('%d不是回文数' % num)