题目链接:hdu 5412 CRB and Queries
首先对所有出现过的值排序,建立线段树,每个线段树的节点是一棵笛卡尔树,笛卡尔树记录区间下标值。
#include
#include
#include
#include
using namespace std;
#define lson(x) (x<<1)
#define rson(x) ((x<<1)|1)
const int maxn = 2 * 1e5 + 5;
const int inf = 0x3f3f3f3f;
int idx;
struct Node {
int key, val, cnt, siz, ch[2];
}nd[maxn * 20];
int root[maxn << 2];
void init () {
idx = 0;
//nd[idx].key = 0;
nd[idx].val = -inf;
nd[idx].cnt = nd[idx].siz = 0;
//nd[idx].ch[0] = nd[idx].ch[1] = 0;
}
int newNode (int key) {
idx++;
nd[idx].key = key;
nd[idx].val = rand();
nd[idx].cnt = nd[idx].siz = 1;
nd[idx].ch[0] = nd[idx].ch[1] = 0;
return idx;
}
void maintain(int u) {
nd[u].siz = nd[nd[u].ch[0]].siz + nd[nd[u].ch[1]].siz + nd[u].cnt;
}
void rotate (int& u, int d) {
int k = nd[u].ch[d];
nd[u].ch[d] = nd[k].ch[d^1];
nd[k].ch[d^1] = u;
maintain(u);
maintain(k);
u = k;
}
void insert (int& u, int key) {
if (u == 0) u = newNode(key);
else if (nd[u].key == key) nd[u].cnt++;
else {
int d = nd[u].key < key;
insert(nd[u].ch[d], key);
if (nd[u].val < nd[nd[u].ch[d]].val) rotate(u, d);
}
maintain(u);
}
void erase (int& u, int key) {
if (nd[u].key == key) {
if (nd[u].cnt == 1) {
if (nd[u].ch[0] == 0 && nd[u].ch[1] == 0) {
u = 0; return;
}
rotate(u, nd[nd[u].ch[0]].val < nd[nd[u].ch[1]].val);
erase(u, key);
} else
nd[u].cnt--;
} else
erase(nd[u].ch[nd[u].key < key], key);
maintain(u);
}
int count (int u, int p) {
if (u == 0) return 0;
if (nd[u].key > p) return count(nd[u].ch[0], p);
return nd[u].cnt + nd[nd[u].ch[0]].siz + count(nd[u].ch[1], p);
}
void modify (int u, int l, int r, int p, int x, int v) {
//if (v < 0)
// printf("%d %d\n", l, r);
if (v > 0) insert(root[u], x);
else erase(root[u], x);
if (l == r) return;
int mid = (l + r) >> 1;
if (p <= mid) modify(lson(u), l, mid, p, x, v);
else modify(rson(u), mid + 1, r, p, x, v);
}
int query (int u, int l, int r, int x, int y, int k) {
//printf("%d %d\n", l, r);
if (l == r) return l;
int mid = (l + r) >> 1;
int siz = count(root[lson(u)], y) - count(root[lson(u)], x);
if (siz >= k) return query(lson(u), l, mid, x, y, k);
else return query(rson(u), mid + 1, r, x, y, k - siz);
}
int N, M, Q, A[maxn], B[maxn], order[maxn], L[maxn], R[maxn], K[maxn];
int find (int x) {
return lower_bound(B, B + M, x) - B + 1;
}
int main () {
while (scanf("%d", &N) == 1) {
memset(root, 0, sizeof(root));
for (int i = 0; i < N; i++) scanf("%d", &A[i]);
for (int i = 0; i < N; i++) B[i] = A[i];
M = N;
scanf("%d", &Q);
for (int i = 0; i < Q; i++) {
scanf("%d%d%d", &order[i], &L[i], &R[i]);
if (order[i] == 1)
B[M++] = R[i];
else
scanf("%d", &K[i]);
}
init();
sort(B, B + M);
M = unique(B, B + M) - B;
for (int i = 0; i < N; i++) {
modify(1, 1, M, find(A[i]), i + 1, 1);
}
for (int i = 0; i < Q; i++) {
if (order[i] == 1) {
modify(1, 1, M, find(A[L[i]-1]), L[i], -1);
A[L[i]-1] = R[i];
modify(1, 1, M, find(A[L[i]-1]), L[i], 1);
} else {
int id = query(1, 1, M, L[i]-1, R[i], K[i]);
printf("%d\n", B[id-1]);
}
}
}
return 0;
}