Pocket Cube HDU - 5983 (简单模拟)

传送门：QAQ

 

题意：两阶魔方能否一次还原

 

代码：

#include
int ax[15][8];
int bn[15][8];
int check() {
    int fla=1;
    for (int i = 0; i < 6; i++) {
        for (int z = 1; z <= 4; z++) {
            if (bn[i][z] != bn[i][1]) {
                fla = 0;
                break;
            }
        }
    }
    return fla;
}
int main(void) {
    int t;
    scanf("%d", &t);
    while (t--) {
        for (int i = 0; i < 6; i++) {
            for (int z = 1; z <= 4; z++) {
                scanf("%d", &ax[i][z]);
                bn[i][z] = ax[i][z];
            }
        }
        if (check()) {
            printf("YES\n");
            continue;
        }
        if (ax[0][1] == ax[0][3] && ax[0][3] == ax[1][2]&& ax[1][2] == ax[1][4] && ax[1][1] == ax[1][3] && ax[1][3] == ax[2][2]&& ax[2][2] == ax[2][4] && ax[2][1] == ax[2][3] && ax[2][3] == ax[3][2]&& ax[3][2] == ax[3][4] && ax[3][1] == ax[3][3] && ax[3][3] == ax[0][2] && ax[0][2] == ax[0][4] && ax[5][1] == ax[5][2] && ax[5][2] == ax[5][3] && ax[5][3] == ax[5][4] && ax[4][1] == ax[4][2] && ax[4][2] == ax[4][3]&& ax[4][3] == ax[4][4]) {
            printf("YES\n");
        }
        else if (ax[0][1] == ax[0][3] && ax[0][3] == ax[3][2]&& ax[3][2] == ax[3][4] && ax[3][1] == ax[3][3] && ax[3][3] == ax[2][2]&& ax[2][2] == ax[2][4] && ax[2][1] == ax[2][3] && ax[2][3] == ax[1][2]&& ax[1][2] == ax[1][4] && ax[1][1] == ax[1][3] && ax[1][3] == ax[0][2]&& ax[0][2] == ax[0][4] && ax[5][1] == ax[5][2] && ax[5][2] == ax[5][3]&& ax[5][3] == ax[5][4] && ax[4][1] == ax[4][2] && ax[4][2] == ax[4][3]&& ax[4][3] == ax[4][4]) {
            printf("YES\n");
        }
        else if (ax[0][2] == ax[0][1] && ax[0][1] == ax[4][4]&& ax[4][4] == ax[4][3] && ax[4][2] == ax[4][1] && ax[4][1] == ax[2][1]&& ax[2][1] == ax[2][2] && ax[2][3] == ax[2][4] && ax[2][4] == ax[5][3] && ax[5][3] == ax[5][4] && ax[5][1] == ax[5][2] && ax[5][2] == ax[0][3]&& ax[0][3] == ax[0][4] && ax[1][1] == ax[1][2] && ax[1][2] == ax[1][3]&& ax[1][3] == ax[1][4] && ax[3][1] == ax[3][2] && ax[3][2] == ax[3][3]&& ax[3][3] == ax[3][4]) {
            printf("YES\n");
        }
        else if (ax[0][2] == ax[0][1] && ax[0][1] == ax[5][4]&& ax[5][4] == ax[5][3] && ax[5][2] == ax[5][1] && ax[5][1] == ax[2][1] && ax[2][1] == ax[2][2] && ax[2][3] == ax[2][4] && ax[2][4] == ax[4][3]&& ax[4][3] == ax[4][4] && ax[4][1] == ax[4][2] && ax[4][2] == ax[0][3]&& ax[0][3] == ax[0][4] && ax[1][1] == ax[1][2] && ax[1][2] == ax[1][3]&& ax[1][3] == ax[1][4] && ax[3][1] == ax[3][2] && ax[3][2] == ax[3][3]&& ax[3][3] == ax[3][4]) {
            printf("YES\n");
        }
        else if (ax[3][2] == ax[3][1] && ax[3][1] == ax[5][1]&& ax[5][1] == ax[5][3] && ax[5][2] == ax[5][4] && ax[5][4] == ax[1][1]&& ax[1][1] == ax[1][2] && ax[1][3] == ax[1][4] && ax[1][4] == ax[4][2]&& ax[4][2] == ax[4][4] && ax[4][1] == ax[4][3] && ax[4][3] == ax[3][3] && ax[3][3] == ax[3][4] && ax[2][1] == ax[2][2] && ax[2][2] == ax[2][3]&& ax[2][3] == ax[2][4] && ax[0][1] == ax[0][2] && ax[0][2] == ax[0][3]&& ax[0][3] == ax[0][4]) {
            printf("YES\n");
        }
        else if (ax[3][4] == ax[3][3] && ax[3][3] == ax[5][2]&& ax[5][2] == ax[5][4] && ax[5][3] == ax[5][1] && ax[5][1] == ax[1][3]&& ax[1][3] == ax[1][4] && ax[1][1] == ax[1][2] && ax[1][2] == ax[4][3]&& ax[4][3] == ax[4][1] && ax[4][4] == ax[4][2] && ax[4][2] == ax[3][1]&& ax[3][1] == ax[3][2] && ax[2][1] == ax[2][2] && ax[2][2] == ax[2][3]&& ax[2][3] == ax[2][4] && ax[0][1] == ax[0][2] && ax[0][2] == ax[0][3]&& ax[0][3] == ax[0][4]) {
            printf("YES\n");
        }
        else printf("NO\n");
    }
    return 0;
}