Determine if a 9x9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules:
A partially filled sudoku which is valid.
The Sudoku board could be partially filled, where empty cells are filled with the character ‘.’.
Input:
[
["5","3",".",".","7",".",".",".","."],
["6",".",".","1","9","5",".",".","."],
[".","9","8",".",".",".",".","6","."],
["8",".",".",".","6",".",".",".","3"],
["4",".",".","8",".","3",".",".","1"],
["7",".",".",".","2",".",".",".","6"],
[".","6",".",".",".",".","2","8","."],
[".",".",".","4","1","9",".",".","5"],
[".",".",".",".","8",".",".","7","9"]
]
Output: true
Input:
[
["8","3",".",".","7",".",".",".","."],
["6",".",".","1","9","5",".",".","."],
[".","9","8",".",".",".",".","6","."],
["8",".",".",".","6",".",".",".","3"],
["4",".",".","8",".","3",".",".","1"],
["7",".",".",".","2",".",".",".","6"],
[".","6",".",".",".",".","2","8","."],
[".",".",".","4","1","9",".",".","5"],
[".",".",".",".","8",".",".","7","9"]
]
Output: false
Explanation: Same as Example 1, except with the 5 in the top left corner being
modified to 8. Since there are two 8's in the top left 3x3 sub-box, it is invalid.
判断是否是一个数独,只要满足数独的条件即可。使用的是最直观的判断方法,还有使用多个boolean数组来判断的简便方法。
public boolean isValidSudoku(char[][] board) {
int[] a= new int[10];
for (int i = 0; i < 9; i++) {
a = new int[10];
for (int j = 0; j < 9; j++) {
if (board[i][j] == '.') { continue; }
int c = board[i][j] - '0';
if (c > 9 || c < 1) { return false; }
if(a[c] != 0) { return false; }
a[c] = 1;
}
}
for (int i = 0; i < 9; i++) {
a = new int[10];
for (int j = 0; j < 9; j++) {
if (board[j][i] == '.') { continue; }
int c = board[j][i] - '0';
if (c > 9 || c < 1) { return false; }
if (a[c] != 0) { return false; }
a[c] = 1;
}
}
for (int i = 0; i < 3; i++) {
for (int j= 0; j < 3; j++) {
a = new int[10];
for (int k = 3 * i; k < 3 * (i + 1); k++) {
for (int l = 3 * j; l < 3 * (j + 1); l++) {
if (board[k][l] == '.') { continue; }
int c = board[k][l] - '0';
if (c < 1 || c > 9) { return false; }
if (a[c] != 0) { return false; }
a[c] = 1;
}
}
}
}
return true;
}