树莓派控制GPIO输入输出,控制步进电机

GIOP输入输出:
其中作为输入,这里写的比较简单,参考一下:
https://blog.csdn.net/qq_41204464/article/details/83446714
https://shumeipai.nxez.com/2016/09/28/rpi-gpio-module-inputs.html

# -*- coding: utf-8 -*-
import RPi.GPIO as GPIO
import time

# 作为输入 接按键 接3.3v 物理引脚1
gpio_1 = 12
# 作为输出  接led 接GND 物理引脚6
gpio_2 = 13


def init():
    GPIO.setmode(GPIO.BOARD)  # 设置引脚的编码方式
    GPIO.setwarnings(False)
    GPIO.setup(gpio_1, GPIO.IN, pull_up_down=GPIO.PUD_DOWN)
    GPIO.setup(gpio_2, GPIO.OUT)


if __name__ == '__main__':
    init()
    while True:
        if GPIO.input(gpio_1):
            print('按钮按下灯亮')
            GPIO.output(gpio_2, GPIO.HIGH)
        else:
            print('Input was LOW')
            GPIO.output(gpio_2, GPIO.LOW)
        time.sleep(1)

然而输入 我这里使用上升沿触发
GPIO.wait_for_edge(channel, GPIO.RISING)
GPIO.add_event_detect(channel, GPIO.RISING)

这些都会出现
RuntimeError: Error waiting for edge
和
RuntimeError: Failed to add edge detection
关于这些错误的资料比较少,网上对于这个的解决很少,解决方法更少,更得的关于GPIO的问题或者权限不足.
其中有一个方法是 在中端检测前加一个延时(我的不行)

后来 我修改了一下自己的代码,检测1000个脉冲

count = 1000
pulse = 0
while pulse < count:
    while GPIO.input(channel) != 0:
        time.sleep(0.001)
    while GPIO.input(channel) == 0:
        time.sleep(0.001)
    water_pulse += 1
    print("脉冲数:", pulse)

控制步进电机:
步进电机:
代码:

import RPi.GPIO as GPIO
import time


gpio_1 = 12
gpio_2 = 13
gpio_3 = 15
gpio_4 = 16


def init():
    GPIO.setmode(GPIO.BOARD)  # 设置引脚的编码方式
    GPIO.setwarnings(False)
    GPIO.setup(gpio_1, GPIO.OUT)
    GPIO.setup(gpio_2, GPIO.OUT)
    GPIO.setup(gpio_3, GPIO.OUT)
    GPIO.setup(gpio_4, GPIO.OUT)


def forward(delay):
    setStep(1, 0, 0, 0)
    time.sleep(delay)
    setStep(0, 1, 0, 0)
    time.sleep(delay)
    setStep(0, 0, 1, 0)
    time.sleep(delay)
    setStep(0, 0, 0, 1)
    time.sleep(delay)


def backward(delay):
    setStep(0, 0, 0, 1)
    time.sleep(delay)
    setStep(0, 0, 1, 0)
    time.sleep(delay)
    setStep(0, 1, 0, 0)
    time.sleep(delay)
    setStep(1, 0, 0, 0)
    time.sleep(delay)


def setStep(w1, w2, w3, w4):
    GPIO.output(gpio_1, w1)
    GPIO.output(gpio_2, w2)
    GPIO.output(gpio_3, w3)
    GPIO.output(gpio_4, w4)


if __name__ == '__main__':
    delay = 2  # delay 2ms
    init()
    print('向前')
    for i in range(3000):
        forward(int(delay) / 1000.0)
    print('向后')
    for i in range(5000):
        backward(int(delay) / 1000.0)
    GPIO.cleanup()
    print('运行结束')

控制电机的另外一种写法:刚想出来的

self.__motor_io_list = [13, 15, 16, 18]
def __motor_controler(self, forward):
    io_value_list = [0, 0, 0, 0]
    for i in range(4):
        if forward:
            pos_neg = i
        else:
            pos_neg = 3 - i
        io_value_list[pos_neg] = 1
        for j in range(4):
            GPIO.output(self.__motor_io_list[j], io_value_list[j])
        io_value_list[pos_neg] = 0
        time.sleep(0.002)

__motor_controler 调用512次转一圈