PAT甲级1058，1059

1058 A+B in Hogwarts （20 point(s)）

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of Galleon.Sickle.Knut (Galleon is an integer in [0,10​7​​], Sickleis an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

题目大意：自定义一个结构的运算，实现这个运算。a.b.c这样一个结构，第一个数范围是0到10的七次方，b是17，c是29

进位搞一下。

解题思路：水是很水，但我还是WA了一发，不知道为什么，第一个数范围明明是有限制的，为什么不考虑溢出的，我现在也不是很懂为什么错。。反正不考虑溢出就对了。

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1059 Prime Factors （25 point(s)）

Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p​1​​​k​1​​​​×p​2​​​k​2​​​​×⋯×p​m​​​k​m​​​​.

Input Specification:

Each input file contains one test case which gives a positive integer N in the range of long int.

Output Specification:

Factor N in the format N = p​1​​^k​1​​*p​2​​^k​2​​*…*p​m​​^k​m​​, where p​i​​'s are prime factors of N in increasing order, and the exponent k​i​​ is the number of p​i​​ -- hence when there is only one p​i​​, k​i​​ is 1 and must NOT be printed out.

Sample Input:

97532468

Sample Output:

97532468=2^2*11*17*101*1291

题目大意：实现一下质因数分解。

解题思路：其实一开始看到这题目脑子里出现的就是打表了。。毕竟运行时间是在你进行输入后开始计算的是吧。后来又想了一下。。long int 能分解的质数最大也就10位吧，直接一个个判断上去不就行了，还搞什么素数判定，直接从2开始分解，不可能存在整除不是质因子的结果呀。

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