查找数组中最大的两个数（Find two Largest Number）

编程的确是个循序渐进的过程，有了基础版，稍微改改就可以添加新功能了，不错，不错！

 

代码如下：

//JHTP Exercise 4.22: Find two Largest Number 
//by [email protected]
/* (Find the Two Largest Numbers) Using an approach similar to that for Exercise 4.21, find
the two largest values of the 10 values entered. [Note: You may input each number only once.*/

import java.util.Scanner;

public class twoLargestNumber {

	public static void main(String[] args) {
		int counter=1;
		int largest=0;
		int secondLargest=0;
		Scanner scanner=new Scanner(System.in);
		int number=0;
		int salesNo=1;
		int largestSalesNo=1;
		int secondLargestSalesNo=1;
		
		while (counter<=10){
			
			System.out.printf("请输入销售员No.%d的销售额:",salesNo);
			number=scanner.nextInt();
			if(number>=largest)
			{
				largest=number;
				largestSalesNo=salesNo;
			}
			if (number>=secondLargest && number

运行结果:

请输入销售员No.1的销售额:12345
请输入销售员No.2的销售额:54321
请输入销售员No.3的销售额:44432
请输入销售员No.4的销售额:67890
请输入销售员No.5的销售额:98760
请输入销售员No.6的销售额:68997
请输入销售员No.7的销售额:43234
请输入销售员No.8的销售额:99987
请输入销售员No.9的销售额:99870
请输入销售员No.10的销售额:103
恭喜销售员No.8创造了最高销售额:99987 RMB
恭喜销售员No.9创造了第二高销售额:99870 RMB