输入输出外挂

写了这场多校的这道题之后，体会到了写对了 输入被卡死 的绝望！要不是中途搞了个外挂，估计要崩溃。所以打算存几个外挂。

适用于纯数字输入：

#include 
using namespace std;

int Scan()  
{  
    int res = 0, ch, flag = 0;  

    if((ch = getchar()) == '-')             //判断正负  
        flag = 1;  

    else if(ch >= '0' && ch <= '9')           //得到完整的数  
        res = ch - '0';  
    while((ch = getchar()) >= '0' && ch <= '9' )  
        res = res * 10 + ch - '0';  

    return flag ? -res : res;  
}  

int main()
{
    int n;
    n = Scan();
    printf("%d\n", n);
}

仅适用于正整数:

#include 
using namespace std;

namespace fastIO { 
    #define BUF_SIZE 100000 
    bool IOerror = 0; 
    inline char nc() { 
        static char buf[BUF_SIZE], *p1 = buf + BUF_SIZE, *pend = buf + BUF_SIZE; 
        if(p1 == pend) { 
            p1 = buf; 
            pend = buf + fread(buf, 1, BUF_SIZE, stdin); 
            if(pend == p1) { 
                IOerror = 1; 
                return -1; 
            } 
        } 
        return *p1++; 
    } 
    inline bool blank(char ch) { 
        return ch == ' ' || ch == '\n' || ch == '\r' || ch == '\t'; 
    } 
    inline void read(int &x) { //将此处改为LL即可输入LL型
        char ch; 
        while(blank(ch = nc())); 
        if(IOerror) 
            return; 
        for(x = ch - '0'; (ch = nc()) >= '0' && ch <= '9'; x = x * 10 + ch - '0'); 
    } 
    #undef BUF_SIZE 
}; 
using namespace fastIO;

int main()
{
    int n;
    read(n);
    printf("%d\n", n);
}