leetCode练习(77)

题目:Combinations          

难度:medium

问题描述:

Given two integers n and k, return all possible combinations ofk numbers out of 1 ... n.

For example,
If n = 4 and k = 2, a solution is:

[
  [2,4],
  [3,4],
  [2,3],
  [1,2],
  [1,3],
  [1,4],
]

解题思路:使用DFS,回溯求解。注意添加判断:剩余字符数小于剩余步数时,不在搜索。可以极大减少迭代次数。

具体代码如下:

public List> combine(int n, int k) {
	   List> reslist=new ArrayList>();
       diedai(new ArrayList(),0,k,1,n,reslist);
       return reslist;
    }
	//可用字符从start到end
	//已经进行step步,一共需要k步
	public void diedai(ArrayList list,int step,int k,int start,int end,List> reslist){
		if((k-step)>(end-start+1)){
			return;
		}
		if(step==k){
			List temp = new ArrayList<>(list);
        	reslist.add(temp);
        	return;
		}
		for(int i=start;i<=end;i++){	
			list.add(i);
			diedai(list,step+1,k,i+1,end,reslist);
			list.remove(list.size()-1);
		}
	}


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