免费午餐问题的引申:
代码如下:
#include
#include
using namespace std;
int total = 0;
vector v1;//原始数据集合
vector v2;//最长不增子序列暂时集合
vector v3;//最长单调递减子序列暂时集合
vector v4;//最长不降子序列暂时集合
vector v5;//最长单调递增子序列暂时集合
//二分法求最长不增子序列关键字下标(>=)
int binarySearch1(int key,int lowIndex,int highIndex)
{
if(lowIndex==highIndex)
{
if(lowIndex == 0 && key>v2[0])
{
return lowIndex;
}
return lowIndex+1;
}
int midIndex = (lowIndex + highIndex + 1)/2;
if(key<=v2[midIndex])
{
return binarySearch1(key,midIndex,highIndex);
}
else
{
return binarySearch1(key,lowIndex,midIndex-1);
}
}
//二分法求最长单调递减子序列关键字下标(>)
int binarySearch2(int key,int lowIndex,int highIndex)
{
if(lowIndex==highIndex)
{
if(keyv2.size()-1)
{
v2.push_back(v1[i]);
}
else
{
v2[lowIndex] = v1[i];
}
//No.2
lowIndex = binarySearch2(v1[i],0,v3.size()-1);
if(lowIndex>v3.size()-1)
{
v3.push_back(v1[i]);
}
else
{
v3[lowIndex] = v1[i];
}
//No.3
lowIndex = binarySearch3(v1[i],0,v4.size()-1);
if(lowIndex>v4.size()-1)
{
v4.push_back(v1[i]);
}
else
{
v4[lowIndex] = v1[i];
}
//NO.4
lowIndex = binarySearch4(v1[i],0,v5.size()-1);
if(lowIndex>v5.size()-1)
{
v5.push_back(v1[i]);
}
else
{
v5[lowIndex] = v1[i];
}
}
cout<<"最长不增子序列长度:"<>n;
for(int i=0;i>a;
v1.push_back(a);
}
if(n!=0)
{
countTotal();
}
return 0;
}