Codeforces Round #275 (Div. 2) --C Diverse Permutation

题目链接:Diverse Permutation



Diverse Permutation
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

Permutation p is an ordered set of integers p1,   p2,   ...,   pn, consisting of n distinct positive integers not larger than n. We'll denote as nthe length of permutation p1,   p2,   ...,   pn.

Your task is to find such permutation p of length n, that the group of numbers |p1 - p2|, |p2 - p3|, ..., |pn - 1 - pn| has exactly k distinct elements.

Input

The single line of the input contains two space-separated positive integers nk (1 ≤ k < n ≤ 105).

Output

Print n integers forming the permutation. If there are multiple answers, print any of them.

Sample test(s)
input
3 2
output
1 3 2
input
3 1
output
1 2 3
input
5 2
output
1 3 2 4 5
Note

By |x| we denote the absolute value of number x.





大致题意:给一个n和k。让找到一种1~n的排列,满足,任意相邻两数之间的差值的绝对值必须为k个不同的值。



解题思路:开始用next_permutation(a, a+n)直接生成排列,然后判断,结果TLE到死。暴力枚举搞不定,那只能构造了。详见代码




AC代码:

#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
using namespace std;
#define INF 0x7fffffff

int a[100005], b[100005];

int main()
{
//     freopen("in.txt","r",stdin);
     int n, k, l, f;
    while(scanf("%d%d",&n,&k)!=EOF)
    {
        f = n - k;                 
        for(int i=1; i<=f; i++){     //构造n-k个差值为1的序列
            printf("%d ", i);
        }
        f ++;
        l = n;
        while(f <= l){               //构造差值为2~k的序列
            printf("%d ", l--);
            if(f <= l)  printf("%d ", f++);
            else   break;
        }
        printf("\n");
    }
    return 0;
}




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