问题
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution.
Example:
Given nums = [2, 7, 11, 15], target = 9,
Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].
The return format had been changed to zero-based indices. Please read the above updated description carefully.
代码
import java.util.HashMap;
public class twoSum {
public int[] twoSum(int[] numbers, int target) {
HashMap map = new HashMap<>();
int[] res = new int[2];
for (int i = 0; i < numbers.length; i++) {
if (map.containsKey(target - numbers[i])) {
res[1] = map.get(target-numbers[i]);
res[0] = i;
break;
}
map.put(numbers[i], i);
}
return res;
}
public static void main(String[] args) {
int [] num = {1,2,3,4,5};
twoSum twoSum = new twoSum();
int[] ints = twoSum.twoSum(num, 6);
for (int i = 0; i < ints.length; i++) {
System.out.println(ints[i]);
}
}
}