Codeforces Round #173 (Div. 2) A.Bit++

好久没做题了，最近又开始做了一些题，找找感觉，从最简单的开始，

A. Bit++

The classic programming language of Bitland is Bit++. This language is so peculiar and complicated.

The language is that peculiar as it has exactly one variable, called x. Also, there are two operations:

• Operation ++ increases the value of variable x by 1.
• Operation -- decreases the value of variable x by 1.

A statement in language Bit++ is a sequence, consisting of exactly one operation and one variable x. The statement is written without spaces, that is, it can only contain characters "+", "-", "X". Executing a statement means applying the operation it contains.

A programme in Bit++ is a sequence of statements, each of them needs to be executed. Executing a programme means executing all the statements it contains.

You're given a programme in language Bit++. The initial value of x is 0. Execute the programme and find its final value (the value of the variable when this programme is executed).

Input

The first line contains a single integer n (1 ≤ n ≤ 150) — the number of statements in the programme.

Next n lines contain a statement each. Each statement contains exactly one operation (++ or --) and exactly one variable x (denoted as letter «X»). Thus, there are no empty statements. The operation and the variable can be written in any order.

Output

Print a single integer — the final value of x.

Sample test(s)

Input

1
++X

Output

1

Input

2
X++
--X

Output

0
就是给几个x++,x--,++x,--x的串然后计算最后x是多少，虽然特别简单，还是写了吧

#include
#include
#include
#include
#include
#include
using namespace std;

char s[3];
int main()
{
    int n;
    while(cin>>n)
    {
        int x=0;
        for(int i=0;i<n;i++)
        {
            cin>>s;
            if(s[1]=='+')
            x++;
            else if(s[1]=='-')
            x--;
        }
        cout<<x<<endl;
    }
    return 0;
}