1074. Reversing Linked List (25)

题目如下：

Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K = 3, then you must output 3→2→1→6→5→4; if K = 4, you must output 4→3→2→1→5→6.

Input Specification:

Each input file contains one test case. For each case, the first line contains the address of the first node, a positive N (<= 10⁵) which is the total number of nodes, and a positive K (<=N) which is the length of the sublist to be reversed. The address of a node is a 5-digit nonnegative integer, and NULL is represented by -1.

Then N lines follow, each describes a node in the format:

Address Data Next

where Address is the position of the node, Data is an integer, and Next is the position of the next node.

Output Specification:

For each case, output the resulting ordered linked list. Each node occupies a line, and is printed in the same format as in the input.

Sample Input:

00100 6 4
00000 4 99999
00100 1 12309
68237 6 -1
33218 3 00000
99999 5 68237
12309 2 33218

Sample Output:

00000 4 33218
33218 3 12309
12309 2 00100
00100 1 99999
99999 5 68237
68237 6 -1

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这是一道著名坑题，如果真的用单向链表来做，实在是太变态了，下面给出一种利用map和vector完成的简单方法。

这道题最大的坑在于有无效结点，也就是说除了从头结点走到-1的所有结点外，还有其他子链表，排除的方法很简单，只要从头到尾走一遍记录下来，其他的全部扔掉。

要解决这个问题，需要考虑以下几个方面：

①如何根据题目输入存储结点？

采用结构体数组，规模为10万，下标即为自己的地址，结构体内存储编号和下一个地址。

②如何进行反转？

只用vector记录有效结点的编号，同时在记录时用map记录编号到地址的对应关系。

只反转vector中的编号。

③如何连接地址输出？

通过反转后的vector，结合map查询地址，实现地址连接。

一定要注意处理K=N和N=1的情况，注意地址的前导0，-1不能有前导0。

代码如下：

#include 
#include 
#include 

转载于:https://www.cnblogs.com/aiwz/p/6154052.html