LeetCode1343

LeetCode1343

/*题目描述:给定一个数组Array、子数组长度k、子数组平均值阀值threshold
 * 		      求出 Array的长度小于k平均值大于等于threshold的子数组的数量。
 *解题思路:维持指针tail指向子数组的尾部、指针head指向子数组头部,声明sum
 *		      记录当前子数组的和,每次将head、tail后移一位,sum=sum-tail+newHead
 *		      若sum/k大于等于threshold,result+1;
 * */
public class Question1343 {
	public static void main(String[] args) {
		int[] arr = {11,13,17,23,29,31,7,5,2,3};
		int k = 3;
		int threshold = 5;
		Question1343_Solution qs = new Question1343_Solution();
		System.out.println(qs.numOfSubarrays(arr, k, threshold));

	}
}

class Question1343_Solution {
    public int numOfSubarrays(int[] arr, int k, int threshold) {
    	//声明子数组尾指针、头指针、和
    	int tail = 0;
    	int head = k-1;
    	int sum = 0;
    	//声明目标子数组的数量
    	int result = 0;
    	//遍历第一个子数组
    	for(int i = 0;i < k; i++) {
    		sum = sum+arr[i];
    	}
    	//遍历arr
    	while(head=threshold) {
    			result++;
    		}
    		if(head+1

 

你可能感兴趣的:(LeetCode,指针,leetcode)