用Kotlin破解Android版微信小游戏-跳一跳

成果

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screenshot.jpg

跳一跳

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微信小程序可以玩游戏了，我们来破解一下《跳一跳》这个官方出品的小游戏吧。

思路

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用usb调试安卓手机，用adb截图并用鼠标测量距离，然后计算按压时间后模拟按压。

$ adb shell input swipe     [duration(ms)] (Default: touchscreen) # 模拟长按
$ adb shell screencap  # 保存截屏到手机
$ adb pull /sdcard/screen.png # 下载截屏文件到本地

1. 得到手指按的时间 t
2. 时间 = 距离 / 速度(常量) t = L / k
3. L = p2 - p1
4. 获取到起始点和结束点的坐标 p1, p2

源码

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开发环境： Kotlin, IetelliJ IDEA

https://github.com/iOSDevLog/JumpJump

主要源码

fun main(args: Array) {
    val jumpjump = JumpJump()
    var isFirst = true
    var firstPoint: Point? = null
    var secondPoint: Point?

    val jPanel = object : JPanel() {
        override fun paintComponent(g: Graphics) {
            super.paintComponent(g)
            try {
                var bufferedImage = ImageIO.read(File(SCREENSHOT_LOCATION))
                val newImage = BufferedImage(675, 1200, bufferedImage.getType())
                val gTemp = newImage.graphics
                gTemp.drawImage(bufferedImage, 0, 0, 675, 1200, null)
                gTemp.dispose()
                bufferedImage = newImage
                g.drawImage(bufferedImage, 0, 0, null)
            } catch (e: IOException) {
                e.printStackTrace()
            }
        }
    }

    jPanel.addMouseListener(object : MouseListener {
        override fun mouseReleased(e: MouseEvent?) {
        }

        override fun mouseEntered(e: MouseEvent?) {
        }

        override fun mouseClicked(e: MouseEvent?) {
        }

        override fun mouseExited(e: MouseEvent?) {
        }

        override fun mousePressed(e: MouseEvent?) {
            println("mousePressed")
            e.let {
                if (isFirst) {
                    println("first {pomt" + e!!.x + " " + e.y)
                    firstPoint = e.point
                    isFirst = false
                } else {
                    secondPoint = e!!.point
                    val distance = distance(firstPoint!!, secondPoint!!)
                    println("distance:" + distance)
                    isFirst = true
                    //magic number
                    call(distance * 2.2)
                    try {
                        // wait for screen cap
                        Thread.sleep(2500)
                    } catch (e1: InterruptedException) {
                        e1.printStackTrace()
                    }

                    printScreen()

                    jPanel.validate()
                    jPanel.repaint()
                }
            }
        }

    })

    jumpjump.isVisible = true
    jumpjump.contentPane.add(jPanel)

    printScreen()
    jumpjump.repaint()
    jumpjump.validate()
}

fun distance(a: Point, b: Point): Int {
    return Math.sqrt((a.x - b.getX()) * (a.x - b.getX()) + (a.y - b.getY()) * (a.y - b.getY())).toInt()
}

使用方法

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1. 在电脑上下载好adb
2. 打开安卓手机的usb调试模式并授权连接的电脑
3. 打开微信跳一跳，并点击开始
4. 在Constans.kt中配置好adb路径与截图路径，运行
5. 在弹出的窗口中先点击小人底部适当位置，然后再点想要跳的箱子的位置即可完成

参考

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https://github.com/easyworld/PlayJumpJumpWithMouse

来源

http://iosdevlog.com/2017/12/29/jump-jump.html

Android 插件 免PC

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screenshot

源码：https://github.com/iOSDevLog/Jump 现在跳得准了。

测试：https://github.com/iOSDevLog/Jump/releases/download/1.0/Jump.apk

视频：https://weibo.com/tv/v/FD5JIDeTO?fid=1034:be8ac5577f9d183858300b1b18a0c782

现在的微信跳一跳小游戏都是通过 PC 端破解的，于是我就写了一个只用 Android 手机就能破解的插件。

如果10秒还不跳，重新回到插件主页再回到跳一跳试试 。

【建议】应该还可以通过Accessibility直接在手机端实现