leetcode练习10：

 

解析：

解法1：转换为字符串

解法2：用数学计算反转

class Solution(object):

    def isPalindrome(self, x):
        """
        :type x: int
        :rtype: bool
        """
        xx = x
        if x < 0:
            return False
        reverse = 0
        while x > 0:
            tmp = x%10
            x = x//10
            #先取余后取整(先取整会改变数字)
            reverse = reverse * 10 + tmp
        return reverse == xx