获取网页源代码并解决字符乱码的问题

给大家推荐个靠谱的公众号程序员探索之路，大家一起加油 ​

每当闲的时候就会刷新一下访问次数，还得刷新页面，作为一个程序员当然不会这么low

写一个程序获得访问次数

package com.lean.zzh;

import java.io.ByteArrayOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;

public class VisitorVolume {

	/**
	 * @param args
	 * @throws IOException
	 */
	public static void main(String[] args) throws IOException {
		// TODO Auto-generated method stub
		URL url = new URL("http://blog.csdn.net/yueloveme");
		System.out.println(getNum(get(url)));
	}

	/**
	 * 获取网页上的源码
	 * 
	 * @throws IOException
	 */
	public static String get(URL url) throws IOException {
		String times = null;
		HttpURLConnection conn = (HttpURLConnection) url.openConnection();
		ByteArrayOutputStream outStream = new ByteArrayOutputStream();
		conn.setRequestMethod("GET");
		conn.setConnectTimeout(5 * 1000);
		InputStream read = conn.getInputStream();
		byte[] infor = new byte[1024];
		int len = 0;
		while ((len = read.read(infor)) != -1) {
			// 网页的编码格式是utf-8的，所以每一次转换都得指定格式才不会乱码
			times += new String(infor, 0, len, "utf-8");
		}
		read.close();
		return times;
	}
	/**
	 * 获取访问量
	 */
	public static String getNum(String information) {
		String num = null;
		int start = information.indexOf("blog_rank");
		start = information.indexOf("", start + 1);
		int end = information.indexOf("", start);
		num = information.substring(start + 6, end);
		return num;
	}
}