求割点和桥的DFS

//无向图求割点和桥
void dfs(int cur,int fa,int deep,int &time)
{
	visit[cur] =  1;
	DFN[cur] = LOW[cur] = deep;
	int soncnt = 0;
	for(int i=0;i=DFN[cur])//割点
			{
				cutv[cur] = 1;
			}
			if(cur==ROOT&&soncnt>=2)//割点
			{
				cutv[cur] = 1;
			}
			if(LOW[v]>DFN[cur])//桥
			{
				Brige[cur][v] = 1;
			}
		}
		else if(v!=fa)
		{
			LOW[cur] = MIN(DFN[v],LOW[cur]);
		}
	}
	LEAVE[cur] = time++;
}