HIVE中的总和模型和漏斗模型sql

--1 
insert into t_salary values ('a','2018-01',10);
insert into t_salary values ('b','2018-01',20);
insert into t_salary values ('a','2018-02',15);
insert into t_salary values ('b','2018-02',30);
insert into t_salary values ('c','2018-03',10);
insert into t_salary values ('c','2018-03',50);
insert into t_salary values ('a','2018-03',20);


select a."name",a."time",max(a.salary),sum(b.salary) from 
(
select t."name",t."time",sum(t.salary) as salary from t_salary t group by t."name",t."time"
) a
inner join 
(
select t."name",t."time",sum(t.salary) as salary from t_salary t group by t."name",t."time"
) b
on a."name" = b."name"
where b."time" <= a."time"
group by a."name",a."time"
order by a."name",a."time";

--2 漏斗模型
insert into t_test_1 values (1,10000);
insert into t_test_1 values (2,4000);
insert into t_test_1 values (3,800);
insert into t_test_1 values (4,100);
insert into t_test_1 values (5,50);
insert into t_test_1 values (6,20);


select * from t_test_1 a
left join t_test_1 b on a."id"-1 = b."id";

select a."id",max(a."number") step_now,
round(cast(max(a."number") as numeric )/cast (max(b."number") as numeric),2) step_one,
round(cast(max(a."number") as numeric )/cast (min(b."number") as numeric),2) step_last
from t_test_1 a
left join t_test_1 b on a."id" > b."id"
group by a."id" order by a."id";