在java中编写http 请求时,很多时候需要注意编码问题。因为在url中有如下特殊字符需要注意
空格 - %20
" - %22
# - %23
% - %25
& - %26
( - %28
) - %29
+ - %2B
, - %2C
/ - %2F
: - %3A
; - %3B
< - %3C
= - %3D
> - %3E
? - %3F
@ - %40
\ - %5C
| - %7C
在处理过程中,需要使用URLEncode进行转化。但是需要注意的时,不能直接将一条get请求的URL直接一次性转化,这样会导致各种意想不到的乱码。正确的做法是,以=号为分割界限,将有可能涉及特殊字符的value值进行编码。这样做,使服务端不会因为字段是乱码而接收不到传递的参数
public static String encode(String str) throws UnsupportedEncodingException{
return URLEncoder.encode(str, "utf-8");
}
params
.append("fromJson=")
.append(encode("[{\"id\":30,"
+ "\"name\":\"YUEHANTEST\","
+ "\"catalog\":\"\","
+ "\"schema\":\"YUEHANTEST\","
+ "\"tableName\":\"db_info\","
+ "\"whereSql\":\"\","
+ "\"cols\":\"\\\"id\\\","
+ "\\\"conn_name\\\","
+ "\\\"db_type\\\","
+ "\\\"url\\\","
+ "\\\"user_name\\\","
+ "\\\"password\\\","
+ "\\\"host\\\","
+ "\\\"port\\\","
+ "\\\"db_name\\\","
+ "\\\"note\\\","
+ "\\\"del_flg\\\","
+ "\\\"create_time\\\","
+ "\\\"update_time\\\"\"}]")).append("&")
.append("toDbJson=")
.append(encode("[{\"cols\":\"\\\"id\\\","
+ "\\\"conn_name\\\","
+ "\\\"db_type\\\","
+ "\\\"url\\\","
+ "\\\"user_name\\\","
+ "\\\"password\\\","
+ "\\\"host\\\","
+ "\\\"port\\\","
+ "\\\"db_name\\\","
+ "\\\"note\\\","
+ "\\\"del_flg\\\","
+ "\\\"create_time\\\","
+ "\\\"update_time\\\"\","
+ "\"createSql\":\"\","
+ "\"tableName\":\"db_info\","
+ "\"name\":\"kdl_test\","
+ "\"replaceEnter\":true,"
+ "\"replacement\":\" \","
+ "\"id\":\"26\","
+ "\"catalog\":\"kdl_test\","
+ "\"schema\":null}]"));