2018-11-22数据库

查询SC表中

SELECT TID,Tname FROM Teacher;
SELECT * FROM Teacher;

-- 2.查询出Teacher表中所有老师的姓名
SELECT Tname FROM Teacher;

-- 3.查询出Teacher表中TID为02的老师信息
SELECT * FROM Teacher WHERE TID='02';

-- 4.查询出SC表中成绩等于80分的学生ID
SELECT SID FROM SC WHERE score='80';
  -- 查询出SC表中成绩等于80分的学生ID
SELECT SID FROM SC WHERE score>'80';
  -- 查询出SC表中成绩小于80分的学生ID
SELECT SID FROM SC WHERE score<'80';
  -- 查询出SC表中成绩不等于80分的学生ID
SELECT SID FROM SC WHERE score<>'80';
  -- 查询出SC表中成绩大于等于80分的学生ID
SELECT SID FROM SC WHERE score>='80';
  -- 查询出SC表中成绩大于等于80分的学生ID
SELECT SID FROM SC WHERE score<='80';

-- 5.查询出SC表中成绩等于80且SID不等于01的学生ID
SELECT SID FROM SC WHERE score='80'AND SID <>'01';

-- 6.查询出SC表中成绩等于80且SID不等于01的学生ID,且对学生编号去重
SELECT DISTINCT SID FROM SC WHERE score='80'AND SID <>'01';

-- 7.查询出SC表中成绩小于80的学生ID,并对学生编号去重
SELECT DISTINCT SID FROM SC WHERE score<80;

查询客户表中

-- 1.查询出客户表中,姓王的客户姓名
SELECT customer_name FROM `t_user_customer` WHERE customer_name LIKE'王%';

-- 2.查询出客户表中,姓名包含春字的客户姓名
SELECT customer_name FROM`t_user_customer`WHERE customer_name LIKE'%春%';

-- 3.查询出客户表中,姓名以“梅”字结尾的客户姓名
SELECT customer_name FROM`t_user_customer`WHERE customer_name LIKE'%梅';

-- 4.查询出客户表中,姓名中间的字为“冬”的客户姓名
SELECT customer_name FROM`t_user_customer`WHERE customer_name LIKE'_冬_';

-- 5.查询出客户表中,马什么梅的客户
SELECT customer_name FROM `t_user_customer` WHERE customer_name LIKE'马_梅';

-- 6.查询出客户表中,什么冬梅的客户
SELECT customer_name FROM `t_user_customer`WHERE customer_name LIKE'_冬梅';

-- 7.查询出客户表中,马冬什么的客户
SELECT customer_name FROM `t_user_customer` WHERE customer_name LIKE'马冬_';

-- 8.查询出客户表中,年龄在20到22之间的客户姓名
SELECT customer_name FROM `t_user_customer` WHERE age BETWEEN 20 AND 29;

-- 9.查询出客户表中,数据创建日期在2018-05-23到2018-08-28之间的客户姓名
SELECT customer_name,create_time FROM `t_user_customer`WHERE create_time BETWEEN '2018-05-23' AND '2018-08-29';

-- 10.查询出客户表中,性别为女的,或者年龄小于26岁的客户
SELECT* FROM`t_user_customer` WHERE sex='1'OR age<26;

-- 11.查询出客户表中,所在省份为重庆,新疆,云南的客户信息
SELECT * FROM`t_user_customer` WHERE province IN ('重庆','新疆','云南');

-- 12.查询出客户表中,出生日期为1995-09-25和1995-09-28的客户信息
SELECT * FROM`t_user_customer` WHERE birthday IN('1995-09-25','1995-09-28');

-- 13.查询出客户表中,出生日期为1995-09-25的男客户和1995-09-28的女客户信息
SELECT * FROM`t_user_customer` WHERE (birthday,sex)IN (('1995-09-25','0'),('1995-09-28','1'));

-- 14.查询出客户表中,云南的女客户并且必须是1995-09-28出生的
SELECT* FROM `t_user_customer` WHERE (birthday,sex,province)IN (('1995-09-28','1','云南'));
SELECT *FROM`t_user_customer` WHERE birthday='1995-09-28' AND province='云南' AND sex='1';

-- 15.查询出客户表中,云南的女客户并且必须是1995-09-28出生的或者新疆的男客户并且在1995-09-25出生的
ELECT* FROM `t_user_customer` WHERE (birthday,sex,province)IN (('1995-09-28','1','云南')('1995-09-25','0','新疆'));

-- 16.查询出客户表中,姓名中不包含冬字的客户姓名
SELECT * FROM `t_user_customer` WHERE customer_name NOT LIKE '%冬%';
SELECT * FROM `t_user_customer` WHERE customer_name <>'冬';

10.-- 10.查询出客户表中,性别为女的,或者年龄小于26岁的客户
SELECT* FROMt_user_customer WHERE sex='1'OR age<26;

-- 11.查询出客户表中,所在省份为重庆,新疆,云南的客户信息
SELECT * FROMt_user_customer WHERE province IN ('重庆','新疆','云南');

-- 12.查询出客户表中,出生日期为1995-09-25和1995-09-28的客户信息
SELECT * FROMt_user_customer WHERE birthday IN('1995-09-25','1995-09-28');

-- 13.查询出客户表中,出生日期为1995-09-25的男客户和1995-09-28的女客户信息
SELECT * FROMt_user_customer WHERE (birthday,sex)IN (('1995-09-25','0'),('1995-09-28','1'));

-- 14.查询出客户表中,云南的女客户并且必须是1995-09-28出生的
SELECT* FROM t_user_customer WHERE (birthday,sex,province)IN (('1995-09-28','1','云南'));
SELECT *FROMt_user_customer WHERE birthday='1995-09-28' AND province='云南' AND sex='1';

-- 15.查询出客户表中,云南的女客户并且必须是1995-09-28出生的或者新疆的男客户并且在1995-09-25出生的
ELECT* FROM t_user_customer WHERE (birthday,sex,province)IN (('1995-09-28','1','云南')('1995-09-25','0','新疆'));

-- 16.查询出客户表中,姓名中不包含冬字的客户姓名
SELECT customer_name FROM t_user_customer WHERE customer_name NOT LIKE '%冬%';

-- 17.查询出客户表中,省份不是重庆且年龄不为28
SELECT customer_name FROMt_user_customer WHERE (province,age) NOT IN (('重庆',28));

-- 课后练习

-- 1.查询出客户表中,年龄大于20的客户
SELECT* FROM`t_user_customer` WHERE age>20;

-- 2.查询出客户表中,年龄小于20的客户
SELECT* FROM`t_user_customer` WHERE age<20;

-- 3.查询出客户表中,年龄大于等于30的客户
SELECT* FROM`t_user_customer` WHERE age>=20;

-- 4.查询出客户表中,年龄小于等于30的客户
SELECT* FROM`t_user_customer` WHERE age<=20;

-- 5.查询出客户表中,年龄不等于20的客户
SELECT* FROM`t_user_customer` WHERE age<>20;

-- 6.查询出客户表中,姓名为周仕平的客户
SELECT * FROM `t_user_customer` WHERE customer_name='周仕平';

-- 7.查询出客户表中,姓周的客户   
SELECT * FROM `t_user_customer` WHERE customer_name LIKE '周%';

-- 8.查询出客户表中,查询用户id 在 50到60之间的客户
SELECT *FROM `t_user_customer` WHERE customer_id BETWEEN 50 AND 60;

-- 9.查询出客户表中,年龄在22-30岁之间的客户
SELECT * FROM `t_user_customer` WHERE age BETWEEN 22 AND 30;

-- 10.查询出客户表中,姓名包含 ’令 ’字或者 ‘伟’字的客户
SELECT customer_name FROM `t_user_customer` WHERE customer_name LIKE'%令%'OR customer_name LIKE'%伟%';

-- 11.查询出客户表中,闵行区的男客户
SELECT customer_name FROM`t_user_customer` WHERE (city,sex)IN (('闵行区','男'));
-- 12.查询出客户表中,姓王并且年龄在25到28之间的客户
SELECT * FROM `t_user_customer` WHERE customer_name LIKE '王%' AND age BETWEEN 25 AND 28;
-- 13.查询出客户表中,年龄大于22岁不姓王的客户
SELECT * FROM `t_user_customer` WHERE customer_name NOT LIKE '王%'AND age>22 ;
-- 14.查询出客户表中,年龄小于30岁,手机号号段为155的客户姓名,年龄,性别,省份,城市和手机号
SELECT customer_name,age,sex,province,city,phone FROM`t_user_customer` WHERE age<30 AND phone LIKE '155%';
-- 15.查询出客户表中,年龄为22,25,27,29的客户
SELECT* FROM`t_user_customer` WHERE age IN ('22','25','27');
-- 16.查询出客户表中,河南平顶山,重庆开县,山东临沂,上海闵行区的客户
SELECT *FROM`t_user_customer` WHERE (province,city)IN (('河南','平顶山'),('山东','临沂')) ;

-- 17.查询出客户表中,年龄为23,24,27,29的女客户
SELECT* FROM`t_user_customer`WHERE age IN ('23','24','27','29')AND sex='女';

-- 18.查询出客户表中,河南洛阳,重庆渝中,山东烟台,上海黄浦区的男客户
SELECT *FROM`t_user_customer` WHERE (province,city)IN (('河南','洛阳'),('重庆','渝中'),('山东','烟台'),('上海','黄浦区'))AND sex='男';

-- 19.查询出客户表中,年龄大于25 小于22的客户
SELECT * FROM `t_user_customer` WHERE age>25,customer_name<22;

--  20.查询出客户表中,名字中不包含明字的男客户
SELECT * FROM t_user_customer WHERE customer_name NOT LIKE '%明%' AND sex = '男';
-- 21.查询出客户表中,非重庆开县,河北沧州,河南洛阳的客户
SELECT * FROM t_user_customer WHERE (province,city) 
NOT IN (('重庆','开县'),('河北','沧州'),('河南','洛阳'));
问题:
 -- 1、查询“001”课程比“002”课程成绩高的所有学生的学号
 select a.S# from (select s#,score from SC where C#='001') a,(select s#,score from SC where C#='002') b where a.score>b.score and a.s#=b.s#; 

2、查询平均成绩大于60分的同学的学号和平均成绩
 select S#,avg(score) from sc group by S# having avg(score) >60; 

3、查询所有同学的学号、姓名、选课数、总成绩
select Student.S#,Student.Sname,count(SC.C#),sum(score) from Student left Outer join SC on Student.S#=SC.S# group by Student.S#,Sname
 
4、查询姓“李”的老师的个数
select count(distinct(Tname)) from Teacher where Tname like '李%';
 
5、查询没学过“叶平”老师课的同学的学号、姓名
 select Student.S#,Student.Sname from Student where S# not in (select distinct( SC.S#) from SC,Course,Teacher where  SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='叶平');
 
6、查询学过“001”并且也学过编号“002”课程的同学的学号、姓名
select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#='001'and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='002'); 

7、查询学过“叶平”老师所教的所有课的同学的学号、姓名
 select S#,Sname from Student where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='叶平' group by S# having count(SC.C#)=(select count(C#) from Course,Teacher  where Teacher.T#=Course.T# and Tname='叶平')); 

8、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名
 Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2 from Student,SC where Student.S#=SC.S# and C#='001') S_2 where score2 60); 

10、查询没有学全所有课的同学的学号、姓名
 select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# group by  Student.S#,Student.Sname having count(C#) <(select count(C#) from Course);
 
11、查询至少有一门课与学号为“1001”的同学所学相同的同学的学号和姓名
 select distinct S#,Sname from Student,SC where Student.S#=SC.S# and SC.C# in (select C# from SC where S#='1001'); 

12、查询至少学过学号为“001”同学所有一门课的其他同学学号和姓名
 select distinct SC.S#,Sname from Student,SC where Student.S#=SC.S# and C# in (select C# from SC where S#='001'); 

13、把“SC”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩
 update SC set score=(select avg(SC_2.score) from SC SC_2 where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname='叶平'); 

14、查询和“1002”号的同学学习的课程完全相同的其他同学学号和姓名
 select S# from SC where C# in (select C# from SC where S#='1002') group by S# having count(*)=(select count(*) from SC where S#='1002'); 

15、删除学习“叶平”老师课的SC表记录 
 Delect SC from course ,Teacher where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='叶平'; 

16.向SC表中插入一些记录,这些记录要求符合以下条件:没有上过编号“003”课程的同学学号、2、号课的平均成绩; 
Insert SC select S#,'002',(Select avg(score)  from SC where C#='002') from Student where S# not in (Select S# from  SC where C#='002'); 

17.按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩,按如下形式显示: 学生ID,,数据库,企业管理,英语,有效课程数,有效平均分 
   SELECT S# as 学生ID ,
(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='004')AS 数据库
 ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='001') AS 企业管理 
 ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='006') AS 英语 
 ,COUNT(*) AS 有效课程数, AVG(t.score) AS 平均成绩 
FROM SC AS t 

GROUP BY S# 

ORDER BY avg(t.score)  

18、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分 
SELECT L.C# As 课程ID,L.score AS 最高分,R.score AS 最低分 FROM SC L ,SC AS R 
WHERE L.C# = R.C# and 
  L.score = (SELECT MAX(IL.score) 
 FROM SC AS IL,Student AS 
WHERE L.C# = IL.C# and IM.S#=IL.S#  GROUP BY IL.C#)
AND R.Score = (SELECT MIN(IR.score)  FROM SC AS IR 
WHERE R.C# = IR.C#   GROUP BY IR.C# ); 

19、按各科平均成绩从低到高和及格率的百分数从高到低顺序 
SELECT t.C# AS 课程号,max(course.Cname)AS 课程名,isnull(AVG(score),0) 
AS 平均成绩  ,100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分数 FROM SC T,Course    
where t.C#=course.C# GROUP BY t.C# 
ORDER BY 100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC

20、查询如下课程平均成绩和及格率的百分数(用"1行"显示): 企业管理(001),马克思(002),OO&UML (003),数据库(004)
  SELECT SUM(CASE WHEN C# ='001' THEN score ELSE 0 END)/SUM(CASE C# WHEN '001' THEN 1 ELSE 0 END) AS 企业管理平均分 
,100 * SUM(CASE WHEN C# = '001' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '001' THEN 1 ELSE 0 END) AS 企业管理及格百分数 
 ,SUM(CASE WHEN C# = '002' THEN score ELSE 0 END)/SUM(CASE C# WHEN '002' THEN 1 ELSE 0 END) AS 马克思平均分 
   ,100 * SUM(CASE WHEN C# = '002' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '002' THEN 1 ELSE 0 END) AS 马克思及格百分数 
 ,SUM(CASE WHEN C# = '003' THEN score ELSE 0 END)/SUM(CASE C# WHEN '003' THEN 1 ELSE 0 END) AS UML平均分
  ,100 * SUM(CASE WHEN C# = '003' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '003' THEN 1 ELSE 0 END) AS UML及格百分数 
,SUM(CASE WHEN C# = '004' THEN score ELSE 0 END)/SUM(CASE C# WHEN '004' THEN 1 ELSE 0 END) AS 数据库平均分
  ,100 * SUM(CASE WHEN C# = '004' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '004' THEN 1 ELSE 0 END) AS 数据库及格百分数 

21、查询不同老师所教不同课程平均分从高到低显示
SELECT max(Z.T#) AS 教师ID,MAX(Z.Tname) AS 教师姓名,C.C# AS 课程ID,MAX(C.Cname) AS 课程名称,AVG(Score) AS 平均成绩
FROM SC AS T,Course AS C ,Teacher AS Z 
where T.C#=C.C# and C.T#=Z.T# 
GROUP BY C.C# 
ORDER BY AVG(Score) DESC 

22、查询学生平均成绩及其名次 
SELECT S#,AVG(score) AS 平均成绩   
FROM SC  GROUP BY S#   ) AS T1
WHERE 平均成绩 > T2.平均成绩) as 名次, S# as 学生学号,平均成绩  FROM (SELECT S#,AVG(score) 平均成绩  FROM SC  GROUP BY S#  ) AS T2    ORDER BY 平均成绩 desc;

23、查询各科成绩前三名的记录:(不考虑成绩并列情况) 
SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数   FROM SC t1 
WHERE score IN (SELECT TOP 3 score 
FROM SC  WHERE t1.C#= C#  ORDER BY score DESC  ) 
ORDER BY score DESC  ORDER BY t1.C#; 

24、查询每门课程被选修的学生数 
select c#,count(S#) from sc group by C#; 

25、查询出只选修了一门课程的全部学生的学号和姓名 
select SC.S#,Student.Sname,count(C#) AS 选课数  from SC ,Student 
where SC.S#=Student.S# group by SC.S# ,Student.Sname having count(C#)=1; 

26、查询男生、女生人数 
Select count(Ssex) as 男生人数 from Student group by Ssex having Ssex='男'; 
Select count(Ssex) as 女生人数 from Student group by Ssex having Ssex='女';

27、查询姓“张”的学生名单 
SELECT Sname FROM Student WHERE Sname like '张%';

28、查询同名同性学生名单,并统计同名人数 
select Sname,count(*) from Student group by Sname having  count(*)>1;; 

29、1981年出生的学生名单(注:Student表中Sage列的类型是datetime) 
select Sname,  CONVERT(char (11),DATEPART(year,Sage)) as age from student 
where  CONVERT(char(11),DATEPART(year,Sage))='1981'; 

30、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列 
Select C#,Avg(score) from SC group by C# order by Avg(score),C# DESC ;

31、、查询平均成绩大于85的所有学生的学号、姓名和平均成绩 
select Sname,SC.S# ,avg(score)   from Student,SC 
where Student.S#=SC.S# group by SC.S#,Sname having    avg(score)>85;

32、查询课程名称为“数据库”,且分数低于60的学生姓名和分数 
Select Sname,isnull(score,0)    from Student,SC,Course 
where SC.S#=Student.S# and SC.C#=Course.C# and  Course.Cname='数据库'and score <60; 

33、查询所有学生的选课情况; 
SELECT SC.S#,SC.C#,Sname,Cname   FROM SC,Student,Course 
where SC.S#=Student.S# and SC.C#=Course.C# ; 

34、查询任何一门课程成绩在70分以上的姓名、课程名称和分数; 
SELECT  distinct student.S#,student.Sname,SC.C#,SC.score 
FROM student,Sc 
WHERE SC.score>=70 AND SC.S#=student.S#; 

35、查询不及格的课程,并按课程号从大到小排列 
select c# from sc where scor e <60 order by C# ; 

 36、查询课程编号为003且课程成绩在80分以上的学生的学号和姓名; 
select SC.S#,Student.Sname from SC,Student where SC.S#=Student.S# and Score>80 and C#='003'; 

37、求选了课程的学生人数 
select count(*) from sc; 

38、查询选修“叶平”老师所授课程的学生中,成绩最高的学生姓名及其成绩 
select Student.Sname,score  from Student,SC,Course C,Teacher 
where Student.S#=SC.S# and SC.C#=C.C# and C.T#=Teacher.T# and Teacher.Tname='叶平' and SC.score=(select max(score)from SC where C#=C.C# ); 

39、查询各个课程及相应的选修人数 
select count(*) from sc group by C#; 

40、查询不同课程成绩相同的学生的学号、课程号、学生成绩 
select distinct  A.S#,B.score from SC A  ,SC B where A.Score=B.Score and A.C# <>B.C# ; 

41、查询每门功课成绩最好的前两名 
SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数   FROM SC t1 
WHERE score IN (SELECT TOP 2 score  FROM SC    WHERE t1.C#= C#      ORDER BY score DESC )  ORDER BY t1.C#; 

42、统计每门课程的学生选修人数(超过10人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,查询结果按人数降序排列,若人数相同,按课程号升序排列  
select  C# as 课程号,count(*) as 人数  
from  sc   group  by  C# 
order  by  count(*) desc,c#  

43、检索至少选修两门课程的学生学号 
select  S#   from  sc    group  by  s#  having  count(*)  >  =  2 

44、查询全部学生都选修的课程的课程号和课程名 
select  C#,Cname       
from  Course   
where  C#  in  (select  c#  from  sc group  by  c#)  

45、查询没学过“叶平”老师讲授的任一门课程的学生姓名 
select Sname
from Student 
where S# not in (select S# from Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname='叶平'); 

46、查询两门以上不及格课程的同学的学号及其平均成绩 
select S#,avg(isnull(score,0)) from SC where S# in (select S# from SC where score <60 group by S# having count(*)>2)group by S#; 

 47、检索“004”课程分数小于60,按分数降序排列的同学学号 
select S# from SC where C#='004'and score <60 order by score desc; 

48、删除“002”同学的“001”课程的成绩 
 delete from Sc where S#='001'and C#='001';

https://www.cnblogs.com/kun-boke/p/5749900.html 练习

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