查询SC表中
SELECT TID,Tname FROM Teacher;
SELECT * FROM Teacher;
-- 2.查询出Teacher表中所有老师的姓名
SELECT Tname FROM Teacher;
-- 3.查询出Teacher表中TID为02的老师信息
SELECT * FROM Teacher WHERE TID='02';
-- 4.查询出SC表中成绩等于80分的学生ID
SELECT SID FROM SC WHERE score='80';
-- 查询出SC表中成绩等于80分的学生ID
SELECT SID FROM SC WHERE score>'80';
-- 查询出SC表中成绩小于80分的学生ID
SELECT SID FROM SC WHERE score<'80';
-- 查询出SC表中成绩不等于80分的学生ID
SELECT SID FROM SC WHERE score<>'80';
-- 查询出SC表中成绩大于等于80分的学生ID
SELECT SID FROM SC WHERE score>='80';
-- 查询出SC表中成绩大于等于80分的学生ID
SELECT SID FROM SC WHERE score<='80';
-- 5.查询出SC表中成绩等于80且SID不等于01的学生ID
SELECT SID FROM SC WHERE score='80'AND SID <>'01';
-- 6.查询出SC表中成绩等于80且SID不等于01的学生ID,且对学生编号去重
SELECT DISTINCT SID FROM SC WHERE score='80'AND SID <>'01';
-- 7.查询出SC表中成绩小于80的学生ID,并对学生编号去重
SELECT DISTINCT SID FROM SC WHERE score<80;
查询客户表中
-- 1.查询出客户表中,姓王的客户姓名
SELECT customer_name FROM `t_user_customer` WHERE customer_name LIKE'王%';
-- 2.查询出客户表中,姓名包含春字的客户姓名
SELECT customer_name FROM`t_user_customer`WHERE customer_name LIKE'%春%';
-- 3.查询出客户表中,姓名以“梅”字结尾的客户姓名
SELECT customer_name FROM`t_user_customer`WHERE customer_name LIKE'%梅';
-- 4.查询出客户表中,姓名中间的字为“冬”的客户姓名
SELECT customer_name FROM`t_user_customer`WHERE customer_name LIKE'_冬_';
-- 5.查询出客户表中,马什么梅的客户
SELECT customer_name FROM `t_user_customer` WHERE customer_name LIKE'马_梅';
-- 6.查询出客户表中,什么冬梅的客户
SELECT customer_name FROM `t_user_customer`WHERE customer_name LIKE'_冬梅';
-- 7.查询出客户表中,马冬什么的客户
SELECT customer_name FROM `t_user_customer` WHERE customer_name LIKE'马冬_';
-- 8.查询出客户表中,年龄在20到22之间的客户姓名
SELECT customer_name FROM `t_user_customer` WHERE age BETWEEN 20 AND 29;
-- 9.查询出客户表中,数据创建日期在2018-05-23到2018-08-28之间的客户姓名
SELECT customer_name,create_time FROM `t_user_customer`WHERE create_time BETWEEN '2018-05-23' AND '2018-08-29';
-- 10.查询出客户表中,性别为女的,或者年龄小于26岁的客户
SELECT* FROM`t_user_customer` WHERE sex='1'OR age<26;
-- 11.查询出客户表中,所在省份为重庆,新疆,云南的客户信息
SELECT * FROM`t_user_customer` WHERE province IN ('重庆','新疆','云南');
-- 12.查询出客户表中,出生日期为1995-09-25和1995-09-28的客户信息
SELECT * FROM`t_user_customer` WHERE birthday IN('1995-09-25','1995-09-28');
-- 13.查询出客户表中,出生日期为1995-09-25的男客户和1995-09-28的女客户信息
SELECT * FROM`t_user_customer` WHERE (birthday,sex)IN (('1995-09-25','0'),('1995-09-28','1'));
-- 14.查询出客户表中,云南的女客户并且必须是1995-09-28出生的
SELECT* FROM `t_user_customer` WHERE (birthday,sex,province)IN (('1995-09-28','1','云南'));
SELECT *FROM`t_user_customer` WHERE birthday='1995-09-28' AND province='云南' AND sex='1';
-- 15.查询出客户表中,云南的女客户并且必须是1995-09-28出生的或者新疆的男客户并且在1995-09-25出生的
ELECT* FROM `t_user_customer` WHERE (birthday,sex,province)IN (('1995-09-28','1','云南')('1995-09-25','0','新疆'));
-- 16.查询出客户表中,姓名中不包含冬字的客户姓名
SELECT * FROM `t_user_customer` WHERE customer_name NOT LIKE '%冬%';
SELECT * FROM `t_user_customer` WHERE customer_name <>'冬';
10.-- 10.查询出客户表中,性别为女的,或者年龄小于26岁的客户
SELECT* FROMt_user_customer
WHERE sex='1'OR age<26;
-- 11.查询出客户表中,所在省份为重庆,新疆,云南的客户信息
SELECT * FROMt_user_customer
WHERE province IN ('重庆','新疆','云南');
-- 12.查询出客户表中,出生日期为1995-09-25和1995-09-28的客户信息
SELECT * FROMt_user_customer
WHERE birthday IN('1995-09-25','1995-09-28');
-- 13.查询出客户表中,出生日期为1995-09-25的男客户和1995-09-28的女客户信息
SELECT * FROMt_user_customer
WHERE (birthday,sex)IN (('1995-09-25','0'),('1995-09-28','1'));
-- 14.查询出客户表中,云南的女客户并且必须是1995-09-28出生的
SELECT* FROM t_user_customer
WHERE (birthday,sex,province)IN (('1995-09-28','1','云南'));
SELECT *FROMt_user_customer
WHERE birthday='1995-09-28' AND province='云南' AND sex='1';
-- 15.查询出客户表中,云南的女客户并且必须是1995-09-28出生的或者新疆的男客户并且在1995-09-25出生的
ELECT* FROM t_user_customer
WHERE (birthday,sex,province)IN (('1995-09-28','1','云南')('1995-09-25','0','新疆'));
-- 16.查询出客户表中,姓名中不包含冬字的客户姓名
SELECT customer_name FROM t_user_customer
WHERE customer_name NOT LIKE '%冬%';
-- 17.查询出客户表中,省份不是重庆且年龄不为28
SELECT customer_name FROMt_user_customer
WHERE (province,age) NOT IN (('重庆',28));
-- 课后练习
-- 1.查询出客户表中,年龄大于20的客户
SELECT* FROM`t_user_customer` WHERE age>20;
-- 2.查询出客户表中,年龄小于20的客户
SELECT* FROM`t_user_customer` WHERE age<20;
-- 3.查询出客户表中,年龄大于等于30的客户
SELECT* FROM`t_user_customer` WHERE age>=20;
-- 4.查询出客户表中,年龄小于等于30的客户
SELECT* FROM`t_user_customer` WHERE age<=20;
-- 5.查询出客户表中,年龄不等于20的客户
SELECT* FROM`t_user_customer` WHERE age<>20;
-- 6.查询出客户表中,姓名为周仕平的客户
SELECT * FROM `t_user_customer` WHERE customer_name='周仕平';
-- 7.查询出客户表中,姓周的客户
SELECT * FROM `t_user_customer` WHERE customer_name LIKE '周%';
-- 8.查询出客户表中,查询用户id 在 50到60之间的客户
SELECT *FROM `t_user_customer` WHERE customer_id BETWEEN 50 AND 60;
-- 9.查询出客户表中,年龄在22-30岁之间的客户
SELECT * FROM `t_user_customer` WHERE age BETWEEN 22 AND 30;
-- 10.查询出客户表中,姓名包含 ’令 ’字或者 ‘伟’字的客户
SELECT customer_name FROM `t_user_customer` WHERE customer_name LIKE'%令%'OR customer_name LIKE'%伟%';
-- 11.查询出客户表中,闵行区的男客户
SELECT customer_name FROM`t_user_customer` WHERE (city,sex)IN (('闵行区','男'));
-- 12.查询出客户表中,姓王并且年龄在25到28之间的客户
SELECT * FROM `t_user_customer` WHERE customer_name LIKE '王%' AND age BETWEEN 25 AND 28;
-- 13.查询出客户表中,年龄大于22岁不姓王的客户
SELECT * FROM `t_user_customer` WHERE customer_name NOT LIKE '王%'AND age>22 ;
-- 14.查询出客户表中,年龄小于30岁,手机号号段为155的客户姓名,年龄,性别,省份,城市和手机号
SELECT customer_name,age,sex,province,city,phone FROM`t_user_customer` WHERE age<30 AND phone LIKE '155%';
-- 15.查询出客户表中,年龄为22,25,27,29的客户
SELECT* FROM`t_user_customer` WHERE age IN ('22','25','27');
-- 16.查询出客户表中,河南平顶山,重庆开县,山东临沂,上海闵行区的客户
SELECT *FROM`t_user_customer` WHERE (province,city)IN (('河南','平顶山'),('山东','临沂')) ;
-- 17.查询出客户表中,年龄为23,24,27,29的女客户
SELECT* FROM`t_user_customer`WHERE age IN ('23','24','27','29')AND sex='女';
-- 18.查询出客户表中,河南洛阳,重庆渝中,山东烟台,上海黄浦区的男客户
SELECT *FROM`t_user_customer` WHERE (province,city)IN (('河南','洛阳'),('重庆','渝中'),('山东','烟台'),('上海','黄浦区'))AND sex='男';
-- 19.查询出客户表中,年龄大于25 小于22的客户
SELECT * FROM `t_user_customer` WHERE age>25,customer_name<22;
-- 20.查询出客户表中,名字中不包含明字的男客户
SELECT * FROM t_user_customer WHERE customer_name NOT LIKE '%明%' AND sex = '男';
-- 21.查询出客户表中,非重庆开县,河北沧州,河南洛阳的客户
SELECT * FROM t_user_customer WHERE (province,city)
NOT IN (('重庆','开县'),('河北','沧州'),('河南','洛阳'));
问题:
-- 1、查询“001”课程比“002”课程成绩高的所有学生的学号
select a.S# from (select s#,score from SC where C#='001') a,(select s#,score from SC where C#='002') b where a.score>b.score and a.s#=b.s#;
2、查询平均成绩大于60分的同学的学号和平均成绩
select S#,avg(score) from sc group by S# having avg(score) >60;
3、查询所有同学的学号、姓名、选课数、总成绩
select Student.S#,Student.Sname,count(SC.C#),sum(score) from Student left Outer join SC on Student.S#=SC.S# group by Student.S#,Sname
4、查询姓“李”的老师的个数
select count(distinct(Tname)) from Teacher where Tname like '李%';
5、查询没学过“叶平”老师课的同学的学号、姓名
select Student.S#,Student.Sname from Student where S# not in (select distinct( SC.S#) from SC,Course,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='叶平');
6、查询学过“001”并且也学过编号“002”课程的同学的学号、姓名
select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#='001'and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='002');
7、查询学过“叶平”老师所教的所有课的同学的学号、姓名
select S#,Sname from Student where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='叶平' group by S# having count(SC.C#)=(select count(C#) from Course,Teacher where Teacher.T#=Course.T# and Tname='叶平'));
8、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名
Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2 from Student,SC where Student.S#=SC.S# and C#='001') S_2 where score2 60);
10、查询没有学全所有课的同学的学号、姓名
select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# group by Student.S#,Student.Sname having count(C#) <(select count(C#) from Course);
11、查询至少有一门课与学号为“1001”的同学所学相同的同学的学号和姓名
select distinct S#,Sname from Student,SC where Student.S#=SC.S# and SC.C# in (select C# from SC where S#='1001');
12、查询至少学过学号为“001”同学所有一门课的其他同学学号和姓名
select distinct SC.S#,Sname from Student,SC where Student.S#=SC.S# and C# in (select C# from SC where S#='001');
13、把“SC”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩
update SC set score=(select avg(SC_2.score) from SC SC_2 where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname='叶平');
14、查询和“1002”号的同学学习的课程完全相同的其他同学学号和姓名
select S# from SC where C# in (select C# from SC where S#='1002') group by S# having count(*)=(select count(*) from SC where S#='1002');
15、删除学习“叶平”老师课的SC表记录
Delect SC from course ,Teacher where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='叶平';
16.向SC表中插入一些记录,这些记录要求符合以下条件:没有上过编号“003”课程的同学学号、2、号课的平均成绩;
Insert SC select S#,'002',(Select avg(score) from SC where C#='002') from Student where S# not in (Select S# from SC where C#='002');
17.按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩,按如下形式显示: 学生ID,,数据库,企业管理,英语,有效课程数,有效平均分
SELECT S# as 学生ID ,
(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='004')AS 数据库
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='001') AS 企业管理
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='006') AS 英语
,COUNT(*) AS 有效课程数, AVG(t.score) AS 平均成绩
FROM SC AS t
GROUP BY S#
ORDER BY avg(t.score)
18、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分
SELECT L.C# As 课程ID,L.score AS 最高分,R.score AS 最低分 FROM SC L ,SC AS R
WHERE L.C# = R.C# and
L.score = (SELECT MAX(IL.score)
FROM SC AS IL,Student AS
WHERE L.C# = IL.C# and IM.S#=IL.S# GROUP BY IL.C#)
AND R.Score = (SELECT MIN(IR.score) FROM SC AS IR
WHERE R.C# = IR.C# GROUP BY IR.C# );
19、按各科平均成绩从低到高和及格率的百分数从高到低顺序
SELECT t.C# AS 课程号,max(course.Cname)AS 课程名,isnull(AVG(score),0)
AS 平均成绩 ,100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分数 FROM SC T,Course
where t.C#=course.C# GROUP BY t.C#
ORDER BY 100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC
20、查询如下课程平均成绩和及格率的百分数(用"1行"显示): 企业管理(001),马克思(002),OO&UML (003),数据库(004)
SELECT SUM(CASE WHEN C# ='001' THEN score ELSE 0 END)/SUM(CASE C# WHEN '001' THEN 1 ELSE 0 END) AS 企业管理平均分
,100 * SUM(CASE WHEN C# = '001' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '001' THEN 1 ELSE 0 END) AS 企业管理及格百分数
,SUM(CASE WHEN C# = '002' THEN score ELSE 0 END)/SUM(CASE C# WHEN '002' THEN 1 ELSE 0 END) AS 马克思平均分
,100 * SUM(CASE WHEN C# = '002' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '002' THEN 1 ELSE 0 END) AS 马克思及格百分数
,SUM(CASE WHEN C# = '003' THEN score ELSE 0 END)/SUM(CASE C# WHEN '003' THEN 1 ELSE 0 END) AS UML平均分
,100 * SUM(CASE WHEN C# = '003' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '003' THEN 1 ELSE 0 END) AS UML及格百分数
,SUM(CASE WHEN C# = '004' THEN score ELSE 0 END)/SUM(CASE C# WHEN '004' THEN 1 ELSE 0 END) AS 数据库平均分
,100 * SUM(CASE WHEN C# = '004' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '004' THEN 1 ELSE 0 END) AS 数据库及格百分数
21、查询不同老师所教不同课程平均分从高到低显示
SELECT max(Z.T#) AS 教师ID,MAX(Z.Tname) AS 教师姓名,C.C# AS 课程ID,MAX(C.Cname) AS 课程名称,AVG(Score) AS 平均成绩
FROM SC AS T,Course AS C ,Teacher AS Z
where T.C#=C.C# and C.T#=Z.T#
GROUP BY C.C#
ORDER BY AVG(Score) DESC
22、查询学生平均成绩及其名次
SELECT S#,AVG(score) AS 平均成绩
FROM SC GROUP BY S# ) AS T1
WHERE 平均成绩 > T2.平均成绩) as 名次, S# as 学生学号,平均成绩 FROM (SELECT S#,AVG(score) 平均成绩 FROM SC GROUP BY S# ) AS T2 ORDER BY 平均成绩 desc;
23、查询各科成绩前三名的记录:(不考虑成绩并列情况)
SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数 FROM SC t1
WHERE score IN (SELECT TOP 3 score
FROM SC WHERE t1.C#= C# ORDER BY score DESC )
ORDER BY score DESC ORDER BY t1.C#;
24、查询每门课程被选修的学生数
select c#,count(S#) from sc group by C#;
25、查询出只选修了一门课程的全部学生的学号和姓名
select SC.S#,Student.Sname,count(C#) AS 选课数 from SC ,Student
where SC.S#=Student.S# group by SC.S# ,Student.Sname having count(C#)=1;
26、查询男生、女生人数
Select count(Ssex) as 男生人数 from Student group by Ssex having Ssex='男';
Select count(Ssex) as 女生人数 from Student group by Ssex having Ssex='女';
27、查询姓“张”的学生名单
SELECT Sname FROM Student WHERE Sname like '张%';
28、查询同名同性学生名单,并统计同名人数
select Sname,count(*) from Student group by Sname having count(*)>1;;
29、1981年出生的学生名单(注:Student表中Sage列的类型是datetime)
select Sname, CONVERT(char (11),DATEPART(year,Sage)) as age from student
where CONVERT(char(11),DATEPART(year,Sage))='1981';
30、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列
Select C#,Avg(score) from SC group by C# order by Avg(score),C# DESC ;
31、、查询平均成绩大于85的所有学生的学号、姓名和平均成绩
select Sname,SC.S# ,avg(score) from Student,SC
where Student.S#=SC.S# group by SC.S#,Sname having avg(score)>85;
32、查询课程名称为“数据库”,且分数低于60的学生姓名和分数
Select Sname,isnull(score,0) from Student,SC,Course
where SC.S#=Student.S# and SC.C#=Course.C# and Course.Cname='数据库'and score <60;
33、查询所有学生的选课情况;
SELECT SC.S#,SC.C#,Sname,Cname FROM SC,Student,Course
where SC.S#=Student.S# and SC.C#=Course.C# ;
34、查询任何一门课程成绩在70分以上的姓名、课程名称和分数;
SELECT distinct student.S#,student.Sname,SC.C#,SC.score
FROM student,Sc
WHERE SC.score>=70 AND SC.S#=student.S#;
35、查询不及格的课程,并按课程号从大到小排列
select c# from sc where scor e <60 order by C# ;
36、查询课程编号为003且课程成绩在80分以上的学生的学号和姓名;
select SC.S#,Student.Sname from SC,Student where SC.S#=Student.S# and Score>80 and C#='003';
37、求选了课程的学生人数
select count(*) from sc;
38、查询选修“叶平”老师所授课程的学生中,成绩最高的学生姓名及其成绩
select Student.Sname,score from Student,SC,Course C,Teacher
where Student.S#=SC.S# and SC.C#=C.C# and C.T#=Teacher.T# and Teacher.Tname='叶平' and SC.score=(select max(score)from SC where C#=C.C# );
39、查询各个课程及相应的选修人数
select count(*) from sc group by C#;
40、查询不同课程成绩相同的学生的学号、课程号、学生成绩
select distinct A.S#,B.score from SC A ,SC B where A.Score=B.Score and A.C# <>B.C# ;
41、查询每门功课成绩最好的前两名
SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数 FROM SC t1
WHERE score IN (SELECT TOP 2 score FROM SC WHERE t1.C#= C# ORDER BY score DESC ) ORDER BY t1.C#;
42、统计每门课程的学生选修人数(超过10人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,查询结果按人数降序排列,若人数相同,按课程号升序排列
select C# as 课程号,count(*) as 人数
from sc group by C#
order by count(*) desc,c#
43、检索至少选修两门课程的学生学号
select S# from sc group by s# having count(*) > = 2
44、查询全部学生都选修的课程的课程号和课程名
select C#,Cname
from Course
where C# in (select c# from sc group by c#)
45、查询没学过“叶平”老师讲授的任一门课程的学生姓名
select Sname
from Student
where S# not in (select S# from Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname='叶平');
46、查询两门以上不及格课程的同学的学号及其平均成绩
select S#,avg(isnull(score,0)) from SC where S# in (select S# from SC where score <60 group by S# having count(*)>2)group by S#;
47、检索“004”课程分数小于60,按分数降序排列的同学学号
select S# from SC where C#='004'and score <60 order by score desc;
48、删除“002”同学的“001”课程的成绩
delete from Sc where S#='001'and C#='001';
https://www.cnblogs.com/kun-boke/p/5749900.html 练习