Nvidia 面试题之一

Nvidia 面试题之一

                    大概的题目是这样的:

                    实现一个函数 void * storenum(struct node* list,int n , int m);

                    作用于分式值小于1的除法. eg: 1/4 = 0.25 这里 m = 4, n = 1 把输出的结果储存到list链表里面

                    

                    

/****************************************
Code writer 	: EOF
code date   	: 2014.10.11
e-mail		: [email protected]

	If you find bugs in my code,
 please touch me, thank you : )
****************************************/
#include 
#include 

struct node
{
	int num;
	struct node* next;
};

int storenum(struct node* list,int m,int n);

int main()
{
	
	struct node header;

	storenum(&header,1,16);

	struct node *p_node = &header;

	/*
	** Print out answer.
	*/
	for(;(p_node->next);)
	{
		printf("%d ",p_node->num);
		p_node = p_node->next;	
	}

	/*
	** Free List we allocated.
	*/
	struct node *del_node = NULL;
	for(p_node = header.next;(header.next);)
	{
		del_node = header.next;
		header.next = del_node->next;
		free(del_node);	
	}

	return 0;
}

int storenum(struct node* list,int m,int n)
{
	if(!list)
	{
		return 0;
	}

	int factor = 10;

	if(m >= n)
	{
		printf("Hey guys read again the rule of this game.!\n");
	}
	else
	{

		list->num  = 0; //0.***
		list->next = NULL;

		for(;m%n != 0;)
		{
			list->next = (struct node*)malloc(sizeof(struct node));
			list->next->next = NULL;
			list = list->next;

			list->num =  m*factor/n;
			m = (m * factor)%n;
		}

			list->next = (struct node*)malloc(sizeof(struct node));
			list->next->next = NULL;
			list = list->next;

			list->num =  m*factor/n;
			m = (m * factor)%n;
	}

	return 0;
}