关于集合的三道编程题

1.图论某班有 40 个学生,学号为 180201-180240, 全部参加 Java 集合阶段检测,给出所有同学的成绩 (可随机产生,范围为 50-100),请编写程序将本班 各位同学成绩从高往低排序打印输出, 注:成绩相同时学号较小的优先打印 要求:打印的信息包含学号、姓名(姓名统一为 “同学 J”[J=10,11,12。。。])和成绩 。

import java.util.*;

/**
 * 描述:从大到小打印学生的:学号+姓名+成绩
 *
 * @Author administrator{GINO ZHANG}
 * @Date2018/11/22
 */
public class JavaTest1 {
    private static List data = new ArrayList();

    static class Student{
        private int id;
        private String name;
        private int score;

        public Student(int id,String name,int score){
            this.id = id;
            this.name = name;
            this.score = score;
        }
        public int getId() {
            return id;
        }
        public String getName() {
            return name;
        }
        public int getScore() {
            return score;
        }

        public String toString() {
            return "学号:" + id +
                    ", 姓名:" + name  +
                    ", 成绩:" + score ;
        }
    }
    public static void initData(){
        int j = 10;
        Random random = new Random();
        for (int i = 0;i < 40;++i){
            data.add(new Student(180201+i,"同学"+(i+j),random.nextInt(51)+50));
        }
    }

    public static void adjust(){
        PriorityQueue queue = new PriorityQueue(11, new Comparator() {
            @Override
            public int compare(Student o1, Student o2) {
                if (o1.getScore() == o2.getScore()) {
                    return o1.getId() - o2.getId();
                }
                return o2.getScore() - o1.getScore();
            }
        });
        Iterator iterator1 = data.iterator();
        while (iterator1.hasNext()){
            queue.add(iterator1.next());
        }

        for (int i = 0; i < 40; i++) {
            System.out.println(queue.remove());
            }


        /**Iterator iterator2 = queue.iterator();
        while (iterator2.hasNext()){
            Student next1 = iterator2.next();
            int id = next1.getId();
            String name = next1.getName();
            int score = next1.getScore();
            System.out.println("学号:"+id+" 姓名:"+name+" 成绩:"+score);
        }*/


    }
    public static void print(){
        Iterator iterator = data.iterator();
        while (iterator.hasNext()){
            Student next1 = iterator.next();
            int id = next1.getId();
            String name = next1.getName();
            int score = next1.getScore();
            System.out.println("学号:"+id+" 姓名:"+name+" 成绩:"+score);
        }
    }



    public static void main(String[] args) {
        JavaTest javaTest = new JavaTest();
        initData();
        adjust();
    }

}

打印结果:

C:\java\java7\jdk1.7.0_80\bin\java.exe -javaagent:D:\ideaIU-2018.1.5.win\lib\idea_rt.jar=61408:D:\ideaIU-2018.1.5.win\bin -
学号:180209, 姓名:同学18, 成绩:100
学号:180224, 姓名:同学33, 成绩:100
学号:180238, 姓名:同学47, 成绩:100
学号:180211, 姓名:同学20, 成绩:98
学号:180212, 姓名:同学21, 成绩:98
学号:180218, 姓名:同学27, 成绩:96
学号:180237, 姓名:同学46, 成绩:94
学号:180210, 姓名:同学19, 成绩:92
学号:180206, 姓名:同学15, 成绩:91
学号:180234, 姓名:同学43, 成绩:91
学号:180240, 姓名:同学49, 成绩:91
.
.
.

Process finished with exit code 0

2.有两个有序的集合,集合的每个元素都是一段范围, 求其交集,例如交集{[4,8],[9,13]}和{[6,12]}的交集是 {[6,8],[9,12]}
/**

  • @param collects1:集合 1
  • @param collects2:集合 2
    */
    public static void intersectionWithColletion (List collects1, List collects2) {
    }

分析:关于集合的三道编程题_第1张图片

import java.util.ArrayList;
import java.util.Iterator;
import java.util.List;

/**
 * 描述:就两个集合的交集
 *
 * @Author administrator{GINO ZHANG}
 * @Date2018/11/21
 */
public class CollectsTest {
    private static boolean isVaild(List> collects) {
        if (collects.size() < 1) {
            System.err.println("两集合无交集");
            return false;
        }
        Iterator> iterator = collects.iterator();
        while (iterator.hasNext()) {
            List  list = iterator.next();
            if (list.size() != 2) {
                System.err.println("集合区间不合法");
                return false;
            }
            if (list.get(0) > list.get(1)) {
                System.err.println("集合区间非有序");
                return false;
            }
        }
        return true;
    }
    public static void intersectionWithColletion(List> collects1, List> collects2) {
        if (!(isVaild(collects1) && isVaild(collects2))) {
            return;
        }
        Iterator > iterator1 = collects1.iterator();
        while (iterator1.hasNext()) {
            List  list1 = iterator1.next();
            Iterator > iterator2 = collects2.iterator();
            while (iterator2.hasNext()) {
                List  list2 = iterator2.next();
                intersection(list1, list2);
            }
        }
    }
    private static void intersection(List list1, List list2) {
        Integer a1 = list1.get(0);
        Integer a2 = list1.get(1);
        Integer b1 = list2.get(0);
        Integer b2 = list2.get(1);

        if (a1 > b2 || b1 > a2) {
            return;
        }
        if (a1 == b2) {
            System.out.println("["+a1+"]");
        }
        if (a2 == b1) {
            System.out.println("["+a2+"]");
        }
        if (a1 >= b1) {
            System.out.print("[" + a1 + ",");
            if (b2 < a2) {
                System.out.println(b2 + "]");
            } else {
                System.out.println(a2 + "]");
            }
        }
        if (b1 >=  a1) {
            System.out.print("["+b1+",");
            if (b2 < a2) {
                System.out.println(b2 + "]");
            } else {
                System.out.println(a2 + "]");
            }
        }
    }

    public static void main(String[] args) {
        ArrayList> a = new ArrayList>();
        ArrayList> b = new ArrayList>();

        ArrayList arrayList1 = new ArrayList();
        arrayList1.add(4);
        arrayList1.add(8);

        ArrayList arrayList2 = new ArrayList();
        arrayList2.add(9);
        arrayList2.add(13);

        ArrayList arrayList3 = new ArrayList();
        arrayList3.add(6);
        arrayList3.add(12);

        a.add(arrayList1);
        a.add(arrayList2);

        b.add(arrayList3);

        intersectionWithColletion(a,b);
    }
}

打印结果:

C:\java\java7\jdk1.7.0_80\bin\java.exe -javaagent:D:\ideaIU-2018.1.5.win\lib\idea_rt.jar=61449:D:\ideaIU-2018.1.5.win\bin -
[6,8]
[9,12]

Process finished with exit code 0

3.一个列表中记录了 1000 条数据[数据内容需 自己初始化产生]。数据内容为部分用户的银行卡 消费记录,消费记录信息包含([姓名] [消费金额]), 找出消费次数最多的用户,并且该用户单笔消费 最高的金额是多少?
例:列表内容格式
张三,666
李四,7893
张三,9999
获取结果则为:张三消费次数最多,最高消费
金额为:9999

import java.util.*;

/**
 * 描述:从随机一千组数据中找出消费记录最多的人,和他的最高的消费额
 *
 * @Author administrator{GINO ZHANG}
 * @Date2018/11/21
 */
public class JavaTest3 {
    static class Person {
        private String name;
        private int money;

        public Person(String name, int money) {
            this.name = name;
            this.money = money;
        }

        public String getName() {
            return name;
        }

        public int getMoney() {
            return money;
        }

        public void setMoney(int money) {
            this.money = money;
        }

        @Override
        public String toString() {
            return "Person{" +
                    "name='" + name + '\'' +
                    ", money=" + money +
                    '}';
        }
    }

    private static ArrayList arrayList = new ArrayList<>();

    public static void initData(List userList) {
        Random random = new Random();
        for (int i = 0; i < 1000; i++) {
            arrayList.add(new Person(userList.get(random.nextInt(3)), random.nextInt(10000)));
        }
    }

    public static void searchUser() {
        HashMap hashMap = new HashMap<>();
        Iterator iterator = arrayList.iterator();
        while (iterator.hasNext()) {
            Person person = iterator.next();
            if (hashMap.containsKey(person.getName())) {
                int value = hashMap.get(person.getName());
                hashMap.put(person.getName(), value + 1);
            } else {
                hashMap.put(person.getName(), 1);
            }
        }

        PriorityQueue> priorityQueue = new PriorityQueue<>(10, new Comparator>() {
            @Override
            public int compare(Map.Entry o1, Map.Entry o2) {
                return o2.getValue() - o1.getValue();
            }
        });
        Iterator> iterator1 = hashMap.entrySet().iterator();
        while (iterator1.hasNext()) {
            Map.Entry value = iterator1.next();
            priorityQueue.add(value);
        }
        //消费次数最多的 最大一笔的金额
        int maxMoney = 0;
        Iterator iterator2 = arrayList.iterator();
        while (iterator2.hasNext()) {
            Person person = iterator2.next();
            String name = priorityQueue.peek().getKey();
            Integer money = person.getMoney();
            while (person.getName().equals(name)) {
                if (person.getMoney() > maxMoney) {
                    maxMoney = person.getMoney();
                } else {
                    break;
                }
            }
        }
        System.out.println(priorityQueue.peek().getKey() + " 为消费次数最多的人" + ",最高消费金额为 :" + maxMoney);
    }

    public static void print() {
        Iterator iterator = arrayList.iterator();
        while (iterator.hasNext()) {
            Person person = iterator.next();
            System.out.println(person + " ");
        }
    }

    public static void main(String[] args) {
        ArrayList arrayList = new ArrayList<>();
        arrayList.add("张三");
        arrayList.add("李四");
        arrayList.add("王五");
        initData(arrayList);
        print();
        searchUser();
    }
}

打印结果:

C:\java\java7\jdk1.7.0_80\bin\java.exe -javaagent:D:\ideaIU-2018.1.5.win\lib\idea_rt.jar=61476:D:\ideaIU-2018.1.5.win\bin -
Person{name='李四', money=8359} 
Person{name='李四', money=1048} 
Person{name='王五', money=3827} 
Person{name='李四', money=2158} 
Person{name='李四', money=553} 
Person{name='王五', money=837} 
Person{name='王五', money=2870} 
Person{name='张三', money=9936} 
.
.
.
张三 为消费次数最多的人,最高消费金额为 :9960

你可能感兴趣的:(java编程)