Problem G: 平面上的点和线——Point类、Line类 (III)

Time Limit: 1 Sec Memory Limit: 128 MB
Submit: 4761 Solved: 2207
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Description

在数学上，平面直角坐标系上的点用X轴和Y轴上的两个坐标值唯一确定，两点确定一条线段。现在我们封装一个“Point类”和“Line类”来实现平面上的点的操作。

根据“append.cc”，完成Point类和Line类的构造方法和show()方法，输出各Line对象和Point对象的构造和析构次序。

接口描述：

Point::show()方法：按格式输出Point对象。

Line::show()方法：按格式输出Line对象。

Input

输入的第一行为N，表示后面有N行测试样例。每行为两组坐标“x,y”，分别表示线段起点和终点的x坐标和y坐标，两组坐标间用一个空格分开，x和y的值都在double数据范围内。

Output

输出为多行，每行为一条线段，起点坐标在前终点坐标在后，每个点的X坐标在前，Y坐标在后，Y坐标前面多输出一个空格，用括号包裹起来。输出格式见sample。

C语言的输入输出被禁用。

Sample Input

40,0 1,11,1 2,32,3 4,50,1 1,0

Sample Output

Point : (1, -2) is created.Point : (2, -1) is created.Point : (0, 0) is created.Point : (0, 0)=========================Point : (0, 0) is created.Point : (1, 1) is created.Line : (0, 0) to (1, 1) is created.Line : (0, 0) to (1, 1)Line : (0, 0) to (1, 1) is erased.Point : (1, 1) is erased.Point : (0, 0) is erased.=========================Point : (1, 1) is created.Point : (2, 3) is created.Line : (1, 1) to (2, 3) is created.Line : (1, 1) to (2, 3)Line : (1, 1) to (2, 3) is erased.Point : (2, 3) is erased.Point : (1, 1) is erased.=========================Point : (2, 3) is created.Point : (4, 5) is created.Line : (2, 3) to (4, 5) is created.Line : (2, 3) to (4, 5)Line : (2, 3) to (4, 5) is erased.Point : (4, 5) is erased.Point : (2, 3) is erased.=========================Point : (0, 1) is created.Point : (1, 0) is created.Line : (0, 1) to (1, 0) is created.Line : (0, 1) to (1, 0)Line : (0, 1) to (1, 0) is erased.Point : (1, 0) is erased.Point : (0, 1) is erased.=========================Point : (1, -2) is copied.Point : (2, -1) is copied.Line : (1, -2) to (2, -1) is created.Point : (1, -2) is copied.Point : (0, 0) is copied.Line : (1, -2) to (0, 0) is created.Point : (2, -1) is copied.Point : (0, 0) is copied.Line : (2, -1) to (0, 0) is created.Point : (0, 0) is copied.Point : (2, -1) is copied.Line : (0, 0) to (2, -1) is created.Line : (1, -2) to (2, -1)Line : (1, -2) to (0, 0)Line : (2, -1) to (0, 0)Line : (0, 0) to (2, -1)Line : (0, 0) to (2, -1) is erased.Point : (2, -1) is erased.Point : (0, 0) is erased.Line : (2, -1) to (0, 0) is erased.Point : (0, 0) is erased.Point : (2, -1) is erased.Line : (1, -2) to (0, 0) is erased.Point : (0, 0) is erased.Point : (1, -2) is erased.Line : (1, -2) to (2, -1) is erased.Point : (2, -1) is erased.Point : (1, -2) is erased.Point : (0, 0) is erased.Point : (2, -1) is erased.Point : (1, -2) is erased.

HINT

Append Code

append.cc,

#include 
#include 
using namespace std;
class Point
{
    friend class Line;
private:
    double x;
    double y;
public:
    Point():x(0),y(0){cout<<"Point : ("<>num;
    for(i = 1; i <= num; i++)
    {
        std::cout<<"=========================\n";
        std::cin>>x1>>c>>y1>>x2>>c>>y2;
        Line line(x1, y1, x2, y2);
        line.show();
    }
    std::cout<<"=========================\n";
    Line l1(p, q), l2(p, t), l3(q, t), l4(t, q);
    l1.show();
    l2.show();
    l3.show();
    l4.show();
}

Problem G: 平面上的点和线——Point类、Line类 (III)