把string转换为char*

https://stackoverflow.com/questions/347949/how-to-convert-a-stdstring-to-const-char-or-char

876 down vote accepted

If you just want to pass a std::string to a function that needs const char* you can use std::string str; const char * c = str.c_str(); If you want to get a writable copy, like char *, you can do that with this: std::string str; char * writable = new char[str.size() + 1]; std::copy(str.begin(), str.end(), writable); writable[str.size()] = '\0'; // don't forget the terminating 0 // don't forget to free the string after finished using it delete[] writable; Edit: Notice that the above is not exception safe. If anything between the new call and the deletecall throws, you will leak memory, as nothing will call delete for you automatically. There are two immediate ways to solve this. boost::scoped_array boost::scoped_array will delete the memory for you upon going out of scope: std::string str; boost::scoped_array writable(new char[str.size() + 1]); std::copy(str.begin(), str.end(), writable.get()); writable[str.size()] = '\0'; // don't forget the terminating 0 // get the char* using writable.get() // memory is automatically freed if the smart pointer goes // out of scope std::vector This is the standard way (does not require any external library). You use std::vector, which completely manages the memory for you. std::string str; std::vector writable(str.begin(), str.end()); writable.push_back('\0'); // get the char* using &writable[0] or &*writable.begin()

876 down vote accepted

If you just want to pass a std::string to a function that needs const char* you can use std::string str; const char * c = str.c_str(); If you want to get a writable copy, like char *, you can do that with this: std::string str; char * writable = new char[str.size() + 1]; std::copy(str.begin(), str.end(), writable); writable[str.size()] = '\0'; // don't forget the terminating 0 // don't forget to free the string after finished using it delete[] writable; Edit: Notice that the above is not exception safe. If anything between the new call and the deletecall throws, you will leak memory, as nothing will call delete for you automatically. There are two immediate ways to solve this. boost::scoped_array boost::scoped_array will delete the memory for you upon going out of scope: std::string str; boost::scoped_array writable(new char[str.size() + 1]); std::copy(str.begin(), str.end(), writable.get()); writable[str.size()] = '\0'; // don't forget the terminating 0 // get the char* using writable.get() // memory is automatically freed if the smart pointer goes // out of scope std::vector This is the standard way (does not require any external library). You use std::vector, which completely manages the memory for you. std::string str; std::vector writable(str.begin(), str.end()); writable.push_back('\0'); // get the char* using &writable[0] or &*writable.begin()